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A piece of ribbon was $\frac{4}{5}$m long. Jean used $\frac{2}{3}$ of the ribbon to decorate a gift. How much ribbon was left.
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The length of Rod A is $\frac{1}{2}$ of the length of Rod B and the length of Rod B is $\frac{1}{3}$ of the length of Rod C and $\frac{1}{4}$ of the length of Rod D. What fraction of the total length of the 4 rods is C?
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1 + 2 + 6 + 8 = 17
$\frac{6}{17}$
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The figure below is made up of identical cubes. If the volume of the figure 104cm$^3$ , what is the length of one edge of a cube?
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A fence is to be built 1m way from the sides of a square filed. Each side of the square is 3pm. Find the total length of the fence needed.
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12p + 8 $\rightarrow$ 1 side of fance $\rightarrow$ 3pm + 1m + 1m = 3p + 2m $\rightarrow$ 4 sides $\rightarrow$ $3p + 2 \times 4 = 12p + 8m$
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12p + 8 $\rightarrow$ 1 side of fance $\rightarrow$ 3pm + 1m + 1m = 3p + 2m $\rightarrow$ 4 sides $\rightarrow$ $3p + 2 \times 4 = 12p + 8m$
Express 8050cm in m.
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Mr Chua had a rectangular piece of cardboard. He cut out 3 semicircles, each with a diagram of 42cm from the cardboard. The perimeter of the remaining piece of cardboard as shown below, not drawn to scale, is 462cm. What is the length of XY?
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51cm $\rightarrow$ 462 – 198 = 264, 78 – 42 = 36, 264 – 36 – 78 = 264, 78 – 42 = 36, 264 – 36 – 78 = 150, 150 ÷ 2 = 75, 75 – 24 = 51
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51cm $\rightarrow$ 462 – 198 = 264, 78 – 42 = 36, 264 – 36 – 78 = 264, 78 – 42 = 36, 264 – 36 – 78 = 150, 150 ÷ 2 = 75, 75 – 24 = 51
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19.18cm $\rightarrow$ 216 ÷ 2 = 108, 108 ÷ 6 = 18
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19.18cm $\rightarrow$ 216 ÷ 2 = 108, 108 ÷ 6 = 18
What is the length of ribbon needed to tie a box as shown if the ribbon goes around the box once, leaving 90cm to tie a box?
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A pieces of ribbon is 5m 20cm long. 60cm of the ribbon is cut off to tie a parcel. After that, the remaining ribbon is cut into 4 equal pieces. What is the length of each piece of ribbon?
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Benjamin has a square piece of paper. He cuts along the dotted lines shown in Figure 1 to get the shaded part and 8 identical isosceles triangles. Triangle PQR in figure 2 is one such triangle with a perimeter of 16cm. The ratio of the perimeter of the square paper to the perimeter of the shaded part is 1:2. Find the length of PQ.
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$12 \times 8 = 96$
$4 \times 4 = 16$
$16 \times 4 = 64$
96 + 16 + 16 = 128
128 ÷ 2 = 64
12 ÷ 2 = 6cm
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$12 \times 8 = 96$
$4 \times 4 = 16$
$16 \times 4 = 64$
96 + 16 + 16 = 128
128 ÷ 2 = 64
12 ÷ 2 = 6cm
The following figure is made up of 4 identical rectangles and a shaded rectangle shaded rectangle The length of BC is 14 cm. if the area of shaded part is 21 cm$^2$. What is the length of EB?
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14 – 3 = 11
11 ÷ 2 = 5.5cm
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14 – 3 = 11
11 ÷ 2 = 5.5cm
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Kevin cut a ribbon measuring 2746m into 20 equal pieces. What is the length of each piece of ribbon? Give your answer in centimeters.
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Jayden painted $\frac{1}{4}$ of a pole red and 2$\frac{2}{5}$m of the pole blue. If the pole was 8m long, what was the length of the pole that was not painted?
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The average mass of a group of 6 adults is 65 kg and the average mass of another group of 4 adults of 80kg. What is the average mass of all the adults in the 2 groups?
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In the diagram below, identical flags are tied to a string that is 17.3m in length. The width of each flag is 1.3m. how many flags are there on the string of there on the string if there is a 0.7m gap between each flag?
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17.3m – 1.3m = 16m
1.3 + 0.7 = 2
16 ÷ 2 = 8
8 + 1 = 9
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17.3m – 1.3m = 16m
1.3 + 0.7 = 2
16 ÷ 2 = 8
8 + 1 = 9
$\frac{7}{8}$m of ribbon was cut into 2 pieces. The shortest piece was 28cm. what is the difference between the longer piece of ribbon and the shorter piece of ribbon?
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31.5cm $\rightarrow$ 28cm = 0.28m, $\frac{7}{8}$m = 0.595m, 0.595m – 0.28m = 0.315m, 0.315m = 31.5cm
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31.5cm $\rightarrow$ 28cm = 0.28m, $\frac{7}{8}$m = 0.595m, 0.595m – 0.28m = 0.315m, 0.315m = 31.5cm
Gabriel has a 3m string. He used 2$\frac{3}{4}$m to tie a carton box and cut the remaining string equally into 5 shorter pieces. What is the length of each of the shorter piece of string?
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Two identical rectangular pieces of plank were together as shown below. The overlapped portion is 28m long. What is the length of each piece of plank before they were nailed together?
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Which of the following is the most likely ratio of the length of the Singapore flag to its breadth?
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AB and BC ate two sides of a trapezium. BC//AD and the length of BC and AD are in the ration of 2:3. Measure the length of CD.
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A piece of a jigsaw puzzle has 3 identical semicircles cut out form a rectangular piece of cardboard as shown figure below. The perimeter of this piece of jigsaw is 84 cm and the diameter of each semicircle is 7cm. Find the length of AB.
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$\frac{3}{2} \times \frac{22}{7} \times 7 = 33$ ,
84 – 33 – 16 – 9 = 26
26 ÷ 2 = 13 Length of AB = 13 + 7 = 20
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$\frac{3}{2} \times \frac{22}{7} \times 7 = 33$ ,
84 – 33 – 16 – 9 = 26
26 ÷ 2 = 13 Length of AB = 13 + 7 = 20
The figure below is made up of 2 overlapping squares. The area of the shaded part is 44cm$^2$. What is the length of the smaller square?
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Peter had a piece of string that was 3.05 m long. He cut off 2.5 m from it. What is the length of the remaining string?
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Hannah uses part of a ruler to measure the length of a pencil. What is the length of the pencil as shown in the figure below?
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Spencer drew 3 lines of different lengths on a piece of paper. The total length of the 3 lines measured 42cm at first. When he doubled the length of the first line, halved the second line and increase the third line by 7cm, the 3 lines become equal in length. What was the length of the longest line at first?
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The graph below shows the length of two springs when an object was hung on each spring. Find the length of each spring that was stretched for every 10g of the object.
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Spring A: 0.9cm. Spring B: 0.6cm $\rightarrow$ A 220g $\rightarrow$ 20cm – 2cm = 18cm, divide by 20 = A 10g $\rightarrow$ 0.9cm, divided by 30 $\rightarrow$ B 300g $\rightarrow$ 20cm – 2cm = 10cm, B 10g $\rightarrow$ 0.6cm
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Spring A: 0.9cm. Spring B: 0.6cm $\rightarrow$ A 220g $\rightarrow$ 20cm – 2cm = 18cm, divide by 20 = A 10g $\rightarrow$ 0.9cm, divided by 30 $\rightarrow$ B 300g $\rightarrow$ 20cm – 2cm = 10cm, B 10g $\rightarrow$ 0.6cm
A rectangular tank was 23cm long. 37cm wide and had a height of 10cm Jake managed to fit a maximum of 90 identical cubes into the tank and cover it with a lid. What is the length of one side of each cube?
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Billy used a piece of string to hold some colored flags, each 10cm wide, as shown in the diagram below. Each flag was strung 20cm apart from one another. Billy also gave an allowance of 40cm each before the first flag and after the last. If the length of the string used was 13.2m, how many flags did he string altogether?
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42 $\rightarrow$ 42 $\rightarrow$ 13 2m = 1320cm, 1320cm – 40cm – 40cm- = 1240cm, 1240cm – 10cm – 10cm – 20cm = 1200cm, 1grp $\rightarrow$ 20cm + 10cm = 30cm, nos. of grp $\rightarrow$ 1200cm ÷ 30cm = 40no. of flags $\rightarrow$ 40 + 2 = 42
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42 $\rightarrow$ 42 $\rightarrow$ 13 2m = 1320cm, 1320cm – 40cm – 40cm- = 1240cm, 1240cm – 10cm – 10cm – 20cm = 1200cm, 1grp $\rightarrow$ 20cm + 10cm = 30cm, nos. of grp $\rightarrow$ 1200cm ÷ 30cm = 40no. of flags $\rightarrow$ 40 + 2 = 42
A ribbon was first cut into 2 pieces in the ration 1:3. The longer piece was then cut into two pieces in the ration 3:2. The shortest piece was 20cm shorter than the longest piece. What was the length of the ribbon before it was cut?
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W, x, y and Z have been marked on a piece of string as shown below. The ratio of the length of WX to the length of XY is 2:1. The ratio of the length of WY to the length YZ is 2:5.What is the ratio of the length of XY to that of YZ?
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The length of a school bus is about _________
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The total length of stick B is 9m. Together with stick C, the average length of the tree sticks is 6m. what is the length is stick C?
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Rachel had a piece of ribbon measuring 3 m 4 cm long. She cut off 7.8 cm of the ribbon. Find the length of the remaining ribbon in cm.
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3m 4cm = 304cm
304 -8 =296
296 – 0.7cm = 295.3cm
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3m 4cm = 304cm
304 -8 =296
296 – 0.7cm = 295.3cm
Mrs Conchie bought 6m 20cm of ribbon and used up $\frac{3}{4}$ of it. She cut the remaining ribbon into 5 equal strips. How long is each strip of ribbon?
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$(\frac{1}{4} \times 6.2) ÷ 5 = 0.31m$
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$(\frac{1}{4} \times 6.2) ÷ 5 = 0.31m$
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Siva had a of ribbon .She cut the ribbon into shorter pieces of different lengths. When she arranged the shorter pieces of ribbons in ascending order of their lengths, the difference in length between any 2 consecutive piece was 1.35 cm.
(a) The length of the third shortest piece of ribbon was 4. 45 cm. What was the total length of the first 5 pieces of ribbon, starting from the shortest piece?
(b) The difference in length between the shortest piece of ribbon and the longest piece pf ribbon was 2.16 m. How pieces of ribbon of ribbons of did Siva cut?
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(a) 4.45 – 1.35 – 1.35 = 1.75
$1.75 \times 5 = 8.75$
$1.35 \times 10 = 13.5$
13.5 + 8.75 = 22.25cm
(b) 216 ÷ 1.35 = 160
160 + 1 = 161
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(a) 4.45 – 1.35 – 1.35 = 1.75
$1.75 \times 5 = 8.75$
$1.35 \times 10 = 13.5$
13.5 + 8.75 = 22.25cm
(b) 216 ÷ 1.35 = 160
160 + 1 = 161
The volume of a cuboid with a height of 7m is 252m$^3$. All the sides of the cuboid are whole numbers. Which one the following in not a possible length of the cuboid?
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Marcus wants to make 35 large identical stars ans 20 small identical start using wire. He has made 20 large start and 14 small ones using 12.48m of wire. The length of wire he used for 5 small start is the same as that for 4 large start.
(a) How many small stars can be made with the same length of wire used to make 20 large stars?
(b) What is the length of wire he needs to make the remaining stars?
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20 large + 14small $\rightarrow$ 12.48m
30small $\rightarrow$ 12.48m
14 small $\rightarrow$ $\frac{14}{39} \times 12.48m= 4.48m$
Length of wire for 20 large stars 12.48 – 44.48 = 8m
1 small star $\rightarrow$ 12.48m ÷ 39 = 0.32m
15 large stars $\rightarrow$ $\frac{15}{20} \times 8m = 6m$
Wire needed $\rightarrow$ 6 ÷ 1.92 = 7.92m
(b) No of large and small stars $\rightarrow$ 15 large + 6small
mall stars $\rightarrow$ $0.32m \times 6 = 1.92m$
15 large stars $\rightarrow$ $\frac{15}{20} \times 8m = 6m$
Wire needed $\rightarrow$ 6 + 1.92 = 7.92m
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20 large + 14small $\rightarrow$ 12.48m
30small $\rightarrow$ 12.48m
14 small $\rightarrow$ $\frac{14}{39} \times 12.48m= 4.48m$
Length of wire for 20 large stars 12.48 – 44.48 = 8m
1 small star $\rightarrow$ 12.48m ÷ 39 = 0.32m
15 large stars $\rightarrow$ $\frac{15}{20} \times 8m = 6m$
Wire needed $\rightarrow$ 6 ÷ 1.92 = 7.92m
(b) No of large and small stars $\rightarrow$ 15 large + 6small
mall stars $\rightarrow$ $0.32m \times 6 = 1.92m$
15 large stars $\rightarrow$ $\frac{15}{20} \times 8m = 6m$
Wire needed $\rightarrow$ 6 + 1.92 = 7.92m
A String Y cm long is cut into two pieces. One piece is 5 cm longer than the other. What is the length of the longer piece? Give your answer in items of Y.
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The total surface area of a cube is 150cm$^2$. What is the length of the cube?
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A car and a van set off from Town C in opposite directions at 11:30. The car travelled towards Town A at an average speed of 80km/h. When the car reached Town A at 14:00, the van was still 15km away from Town B. What was the distance between Town A and Town B?
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365km $\rightarrow$ 2h30mins = 2h$\frac{1}{2}$h, 2$\frac{1}{2} \times 80 = 200$, 2$\frac{1}{2} \times 60 + 15 = 165$, 165 + 200 = 365
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365km $\rightarrow$ 2h30mins = 2h$\frac{1}{2}$h, 2$\frac{1}{2} \times 80 = 200$, 2$\frac{1}{2} \times 60 + 15 = 165$, 165 + 200 = 365
A supermarket and a bank 500m apart, are situated between Mrs Ting’s house and Mdm Leela’s house as shown below. The bank is half way between the two houses.
Mrs Ting and mdm Leela left their homes at the same time and arrived at the supermarket at the same time. Mrs Ting drove at a speed of 65 Km/h while Mdm Leela drove at a speed 10 km/h slower than Mrs Ting.
(a) How much further did Mrs Ting travel than Mdm Leela?
(b) How far is Mdm Leela’s house from the bank?
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(a) $500 \times 500 = 1000$
(b) 10km $\rightarrow$ 1h
1km $\rightarrow$ 1h
1km $\rightarrow$ $\frac{1}{10}$h
55 x $\frac{1}{10}$ = 5.5
5.5 + 0.5 = 6km
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(a) $500 \times 500 = 1000$
(b) 10km $\rightarrow$ 1h
1km $\rightarrow$ 1h
1km $\rightarrow$ $\frac{1}{10}$h
55 x $\frac{1}{10}$ = 5.5
5.5 + 0.5 = 6km
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