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Interval Problems

Question 1 of 13

Wahid and Ajay had a total of 1760 marbles. After Wahid gave Ajay 130 marbles, he still had $\frac{3}{4}$ of the total number of marbles. How many marbles did Wahid have at first?

1450

1500

1550

1600

None of the above

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1450

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As shown in the figure below, $\angle$ABCD is a rectangle. $\angle$P is the midpoint of $\angle$AD. $\angle$AQ = $\angle$QR = $\angle$RC. What fraction of the rectangle is shaded?

$Question Image of As shown in the figure below, $\angle$ABCD is a rectangle. $\angle$P is the midpoint of $\angle$AD. $\angle$AQ = $\angle$QR = $\angle$RC. What fraction of the rectangle is shaded?.$

$\frac{1}{2}$

$\frac{1}{4}$

$\frac{1}{6}$

$\frac{1}{8}$

None of the above

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$\frac{1}{4}$

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Mark spent $\frac{1}{10}$ of his salary on transport and$\frac{1}{5}$ of it on food. He also gave $\frac{1}{2}$ of his salary to his parents. He saved the remaining $480.
a) What fraction of the salary did he save?
b) How much money did he give his parents?
c) How much did he spend on food and transport?

a)$\frac{1}{3}$
b) \$1000
c) $220

a)$\frac{1}{5}$
b) \$1200
c) $240

a)$\frac{1}{7}$
b) \$1400
c) $260

a)$\frac{1}{9}$
b) \$1600
c) $280

None of the above

Sorry. Please check the correct answer below.

$\frac{1}{10}$ + $\frac{1}{5}$ + $\frac{1}{2}$ = $\frac{1}{10}$ + $\frac{2}{10}$ + $\frac{5}{10}$ = $\frac{8}{10}$
$\frac{10}{10}$ - $\frac{8}{10}$ = $\frac{2}{10}$
= $\frac{1}{5}$
a) He Saved $\frac{1}{5}$ of the salary.
b) 2 units $\longrightarrow$ \$480
5 units $\longrightarrow$ \$240 $\times$ 5 = \$1200
c) 1 unit = \$240
He spent \$240 on transport.

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a)$\frac{1}{5}$
b) \$1200
c) $240

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1$\frac{1}{4}$m of ribbon is cut into shorter pieces of$\frac{1}{3}$m each. What is the length of the remaining piece?

$\frac{1}{2}$

$\frac{1}{3}$

$\frac{1}{4}$

$\frac{1}{5}$

None of the above

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$\frac{1}{4}$

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$Answer Image$

What fraction of the figure is shaded?

$Question Image$

$\frac{1}{6}$

$\frac{3}{8}$

$\frac{5}{10}$

$\frac{7}{12}$

None of the above

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$\frac{6}{16}$ = $\frac{3}{8}$

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$\frac{3}{8}$

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$\frac{6}{16}$ = $\frac{3}{8}$

Maureen and Serene had a total of 2136 stickers. After Maureen gave Serene 60 stickers, she still had $\frac{2}{3}$ of the total number of stickers. How many stickers did Maureen have at first?

1480

1482

1484

1486

None of the above

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1484

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Nina and Owen have a total of \$320. After Nina gave $\frac{1}{5}$ of her money to Owen, they now have the same amount of money. How much money did Owen have at first?

100

150

200

None of the above

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200

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$Answer Image$

$\frac{1}{4}$ of the children in a hall were girls. After $\frac{1}{3}$ of the girls left, there were 42 more boys than girls remaining in the hall. How many children were in the hall at first?

None of the above

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Find the value of $\frac{2}{7}$ - $\frac{6}{35}$?

$\frac{1}{2}$

1$\frac{2}{3}$

1$\frac{3}{4}$

1$\frac{4}{5}$

None of the above

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1$\frac{2}{3}$

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Find the product of $\frac{3}{7}$ and $\frac{4}{3}$ ?

$\frac{2}{5}$

$\frac{2}{7}$

$\frac{4}{5}$

$\frac{4}{7}$

None of the above

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$\frac{4}{7}$

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$Answer Image$

Kumar had 480 marbles. After giving away most of his marbles to his friends, he still had $\frac{1}{6}$ of the marbles left. How many marbles did he give away?

200

250

400

450

None of the above

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400

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$Answer Image$

Andy gave $\frac{1}{12}$ of his stickers to Alan. He also gave $\frac{1}{3}$ and $\frac{1}{4}$ of his stickers to Ben and Charlie, respectively. He then had 96 stickers left.
a) What fraction his stickers was left?
b) How many stickers did he give to Charlie?

a)$\frac{1}{2}$
b)70

a)$\frac{2}{3}$
b)72

a)$\frac{3}{4}$
b)74

a)$\frac{4}{5}$
b)76

None of the above

Sorry. Please check the correct answer below.

$\frac{1}{12}$ + $\frac{1}{3}$ + $\frac{1}{4}$ = $\frac{1}{12}$ + $\frac{4}{12}$ + $\frac{3}{12}$ = $\frac{8}{12}$ = $\frac{2}{3}$
$\frac{4}{12}$ = 96 stickers
$\frac{1}{12}$ = 24 stickers
$\frac{3}{12}$ = 72 stickers
a) He had $\frac{2}{3}$ of his stickers left.
b) He gave 72 stickers to Charlie.

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a)$\frac{2}{3}$
b)72

You are Right

Find the value of $\frac{1}{2}$ - $\frac{3}{8}$

$\frac{1}{6}$

$\frac{1}{8}$

$\frac{1}{4}$

$\frac{1}{2}$

None of the above

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$\frac{1}{2}$ - $\frac{3}{8}$ = $\frac{4}{8}$ - $\frac{3}{8}$ = $\frac{1}{8}$

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$\frac{1}{8}$

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$\frac{1}{2}$ - $\frac{3}{8}$ = $\frac{4}{8}$ - $\frac{3}{8}$ = $\frac{1}{8}$

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