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Question 1 of 26

The figure, not down to scale, shows a rhombus ABCD. DB is a straight line. Find $\angle$EDC.

$Question Image of The figure, not down to scale, shows a rhombus ABCD. DB is a straight line. Find $\angle$EDC..$

103$^\circ$

105$^\circ$

107$^\circ$

109$^\circ$

None of the above

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105$^\circ$

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In the figure, ABCD and EFGH are identical rhombuses and BKMN is a trapezium. Which one of the following statements is true?

AB // DC //KM

HG // EF // NM

HE // GF // KM

AD // BC // NM

None of the above

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AD // BC // NM

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In the figure below, BCDE is a rhombus and DEA is a straight line. Find the value of $\angle$b.

$Question Image$

52$^\circ$

54$^\circ$

56$^\circ$

58$^\circ$

None of the above

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52$^\circ$

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The figure below shows a rhombus. Which of the following is true?

$Question Image$

$\angle$a = 90$^\circ$

$\angle$b = $\angle$c

$\angle$b + $\angle$d = 180$^\circ$

$\angle$a + $\angle$b = 180$^\circ$

None of the above

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$\angle$a + $\angle$b = 180$^\circ$

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In the figure below, not drawn to scale, ABCD is a rhombus. Given that BCE is a straight line, Find $\angle$p + $\angle$q.

$Question Image$

135$^\circ$

140$^\circ$

145$^\circ$

150$^\circ$

None of the above

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145$^\circ$

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In the diagram below, ABCD is a rhombus. E is the mid–point BC and AC. Find the area the shaded part.

$Question Image$

3cm$^2$

5cm$^2$

7cm$^2$

9cm$^2$

None of the above

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5cm$^2$

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JKLM is a rhombus. Find $\angle$MKL.

$Question Image$

51$^\circ$

53$^\circ$

55$^\circ$

57$^\circ$

None of the above

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$180^\circ - 74^\circ = 106^\circ$
$(180^\circ - 74^\circ) \div 2 = 53^\circ$

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53$^\circ$

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$180^\circ - 74^\circ = 106^\circ$
$(180^\circ - 74^\circ) \div 2 = 53^\circ$

In the figure below, ABCD is a rhombus and CDE is an isosceles triangle. $\angle$CDE = 36$^\circ$ and BCE is a straight line. Find$\angle$x.

$Question Image$

100$^\circ$

102$^\circ$

104$^\circ$

106$^\circ$

None of the above

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102$^\circ$

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The figure is made up of a square, PQRS, and a rhombus, RTSU. Find $\angle$QRU.

$Question Image$

22%

33%

44%

55%

None of the above

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$5 + 1 = 6$
$6 \times 6 = 36$
$36 – 25 = 11$
$5 \times 5 = 25$
$\frac{11}{25} \times 100 = 44%$

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44%

You are Right

$5 + 1 = 6$
$6 \times 6 = 36$
$36 – 25 = 11$
$5 \times 5 = 25$
$\frac{11}{25} \times 100 = 44%$

In the figure below. ABCD is a rhombus, $\angle$ABC =102$^\circ $ and$\angle$CAE=19$^\circ $. Find $\angle$EAB.

$Question Image$

20$^\circ$

30$^\circ$

40$^\circ$

50$^\circ$

None of the above

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20$^\circ$ $\rightarrow$ $180^\circ – 120^\circ = 78^\circ$
$78^\circ ÷ 2 = 39^\circ$
$39^\circ - 19^\circ = 20^\circ$

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20$^\circ$

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20$^\circ$ $\rightarrow$ $180^\circ – 120^\circ = 78^\circ$
$78^\circ ÷ 2 = 39^\circ$
$39^\circ - 19^\circ = 20^\circ$

ABCD is rhombus and $\angle$BCD = 35$^\circ$. BD is a straight line. Find $\angle$BAD.

$Question Image$

80$^\circ$

90$^\circ$

100$^\circ$

110$^\circ$

None of the above

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110$^\circ$

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The figure below is made up of a rectangle ABCD and a rhombus AEBF. Find $\angle$x.

$Question Image$

40$^\circ$

50$^\circ$

60$^\circ$

70$^\circ$

None of the above

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The figure below is made up of a right –angled triangle and a rhombus overlapping each other. $\frac{2}{9}$ of the triangle and $\frac{1}{2}$ of the rhombus are unshaded. The base and height of the triangle are 18cm and 28cm respectively. What is the area of the rhombus?

$Question Image$

392cm$^2$

396cm$^2$

392cm$^3$

396cm$^3$

None of the above

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392cm$^2$ $\rightarrow$ 9u $\rightarrow$ $\frac{1}{2} \times 18cm \times 28cm = 252cm^2$
1U $\rightarrow$ $252cm ÷ 9 = 28cm^2$
14u $\rightarrow$ $28cm^2 \times 14 = 392cm^2$

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392cm$^2$

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392cm$^2$ $\rightarrow$ 9u $\rightarrow$ $\frac{1}{2} \times 18cm \times 28cm = 252cm^2$
1U $\rightarrow$ $252cm ÷ 9 = 28cm^2$
14u $\rightarrow$ $28cm^2 \times 14 = 392cm^2$

The figure not drawn to scale, is made up of a triangle ABC and two rhombuses, PSRQ and PTCU. $\angle$ TPU = 79$^\circ$. Find $\angle$ d + $\angle$ e + $\angle$ f + $\angle$ g.

$Question Image$

303$^\circ$

304$^\circ$

305$^\circ$

306$^\circ$

None of the above

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$\angle$d + $\angle$e = $180^\circ = 79^\circ = 101^\circ$
$\angle$d + $\angle$e + $\angle$f + $\angle$g = $101^\circ + 202^\circ = 303^\circ$

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303$^\circ$

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$\angle$d + $\angle$e = $180^\circ = 79^\circ = 101^\circ$
$\angle$d + $\angle$e + $\angle$f + $\angle$g = $101^\circ + 202^\circ = 303^\circ$

In the figuare, ABCD is a rhombus. ACD, AHF and DEF are straight line. HE is parallel to GF and HE = HF. $\angle$ABC = 110$^\circ$ and $\angle$HFG = 20$^\circ$. Find $\angle$CDE.

$Question Image$

62$^\circ$

65$^\circ$

72$^\circ$

75$^\circ$

None of the above

Sorry. Please check the correct answer below.

$\angle$EHF = $\angle$GFH = 20$^\circ$
$\angle$HEF = $\angle$HFE = $(180 - 20) \div 2 = 80^\circ$
$\angle$CAH = $\angle$HCA = $(180 - 110) \div 2 = 35^\circ$
$\angle$CDE = $180 – 80 – 35 = 65^\circ$

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65$^\circ$

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The figure below is not drawn to scale ABCD is a rhombus. CDF, BCG and EFG are straight line. Find$\angle$y.

$Question Image$

108$^\circ$

109$^\circ$

110$^\circ$

111$^\circ$

None of the above

Sorry. Please check the correct answer below.

$\angle$BAC = $180^\circ - 56^\circ = 124^\circ$
$\angle$DCG = $180^\circ - 124^\circ = 56^\circ$
$\angle$DFG = $180^\circ - 56^\circ - 155^\circ = 69^\circ$
y = $180^\circ - 69^\circ = 111^\circ$
$\angle$y is 111$^\circ$

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111$^\circ$

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In the diagram below, ABCO and FODE are identical rhombuses and AOF and OCD are identical equilateral triangle. What fraction of the figure ABCDEF is shaded?

$Question Image$

$\frac{1}{1}$

$\frac{1}{2}$

$\frac{1}{3}$

$\frac{1}{4}$

None of the above

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$\frac{1}{3}$

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In the figure, ABCD is a rhombus. EDF is a straight line $\angle$BAD = 58$^\circ$, and $\angle$ADE = 78$^\circ$. Find $\angle$FDC.

$Question Image$

None of the above

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View Correct Answer

You are Right

The figure below shows a rhombus divided into 6 parts with 3 straight lines. Find the sum of $\angle$ X and $\angle$ Y.

$Question Image$

210$^\circ$

211$^\circ$

212$^\circ$

213$^\circ$

None of the above

Sorry. Please check the correct answer below.

$360 – 274 = 86$
$(360 – 86 - 86) ÷ 2 = 94$
$(360 – 102 - 102) ÷ 2 = 47$
$360 – 102 – 47 = 221$

View Correct Answer

211$^\circ$

You are Right

$360 – 274 = 86$
$(360 – 86 - 86) ÷ 2 = 94$
$(360 – 102 - 102) ÷ 2 = 47$
$360 – 102 – 47 = 221$

In the figure below, STUV is a parallelogram and VWXS is a rhombus. Which of the following pairs of line are parallel?

$Question Image$

VW and UV

VW and TS

TU and XW

TU and SX

None of the above

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TU and XW

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In the figure below, not drawn to scale, ABCG is a rhombus. BGF, CDF and EDG are straight line, Find
(a) $\angle$x
(b) $\angle$y.

$Question Image$

(a) 200$^\circ$
(b) 22$^\circ$

(a) 202$^\circ$
(b) 24$^\circ$

(a) 204$^\circ$
(b) 26$^\circ$

(a) 206$^\circ$
(b) 28$^\circ$

None of the above

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(a) $\angle$DCG = $90^\circ - 68^\circ = 28^\circ$
$\angle$CGD = $180^\circ - 110^\circ - 28^\circ = 42^\circ$
$\angle$AGC = $360^\circ – \frac{(68 \times2)}{2} = 112^\circ$
$\angle$x = $360^\circ - 112^\circ - 42^\circ = 206^\circ$ (b) $\angle$GBC = $112^\circ ÷ 2 = 56^\circ$
$\angle$y = $180^\circ - 56^\circ -96^\circ = 28^\circ$

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(a) 206$^\circ$
(b) 28$^\circ$

You are Right

In the figure below, ABCD is a rhombus. $\angle$EDB = 97$^\circ$, $\angle$FEG = 110$^\circ$,and $\angle$BAD = 66$^\circ$. Give, that GED, FED and FDB are straight lines, Find$\angle$FCD,

$Question Image$

30$^\circ$

35$^\circ$

40$^\circ$

45$^\circ$

None of the above

Sorry. Please check the correct answer below.

$\angle$CBD $\rightarrow$ $180^\circ – 66^\circ \div 2 = 57^\circ$
$\angle$EDC $\rightarrow$ $97^\circ – 57^\circ = 40^\circ$
$\angle$FCD $\rightarrow$ $180^\circ – 40^\circ – 110^\circ = 30^\circ$

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30$^\circ$

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In the figure below, ABCD is a rhombus and EF is a straight line. Find $\angle$m.

$Question Image$

31$^\circ$

56$^\circ$

62$^\circ$

112$^\circ$

None of the above

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56$^\circ$

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ABCD is a rhombus. Which line is parallel to AB?

$Question Image$

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

You are Right

The figure below is not drawn to scale. ABCD is a rhombus and $\angle$BCF is 98$^\circ$. BDF, CGF, EGD are straight line. Find $\angle$DFG.

$Question Image$

15$^\circ$

18$^\circ$

26$^\circ$

29$^\circ$

None of the above

Sorry. Please check the correct answer below.

$\angle$BDC $\rightarrow$ $(180^\circ - 68^\circ) \div 2 = 56^\circ$ = $\angle$FBC
$\angle$DFG $\rightarrow$ $180^\circ - 56^\circ - 98^\circ = 26^\circ$

View Correct Answer

26$^\circ$

You are Right

$\angle$BDC $\rightarrow$ $(180^\circ - 68^\circ) \div 2 = 56^\circ$ = $\angle$FBC
$\angle$DFG $\rightarrow$ $180^\circ - 56^\circ - 98^\circ = 26^\circ$

The figure below is not drawn to scale. ABCD is a rhombus. DBE is a straight line. BC is parallel to EF. Find $\angle$DEF.

$Question Image$

53$^\circ$

55$^\circ$

57$^\circ$

59$^\circ$

None of the above

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View Correct Answer

55$^\circ$

You are Right

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