In the figure below, ABCD is a rhombus. $\angle$EDB = 97$^\circ$, $\angle$FEG = 110$^\circ$,and $\angle$BAD = 66$^\circ$. Give, that GED, FED and FDB are straight lines, Find$\angle$FCD,

The figure below is made up of a right –angled triangle and a rhombus overlapping each other. $\frac{2}{9}$ of the triangle and $\frac{1}{2}$ of the rhombus are unshaded. The base and height of the triangle are 18cm and 28cm respectively. What is the area of the rhombus?