- Numbers
- What does the number stand for?
- Nearest number
- Which digit is in the place?
- Round off to the nearest number
- Number divide
- Find the fraction nearest to 1
- Sort fraction numbers
- Find the largest or smallest fraction
- Fraction to decimal
- Convert decimal to a mixed fraction.
- Fraction - Addition
- Fraction - Substraction
- Fraction - Multiply
- Fraction - Divide
- List all the common factors of two integers
- Chicken and Rabbit problem
- Assumption Method

- Measurement
- Data Analysis
- Geometry
- Speed
- Others
- P5 Maths
- P4 Maths

- Tap to switch levels
- Numbers
- Measurement
- Data Analysis
- Geometry
- Speed
- Others
- P5 Maths
- P4 Maths

SELECT A SUBJECT

- Numbers

James attended a Chinese Multiple Choices Test. James answered all 77 questions. For each correct answer, James will get 4 marks. However, for each wrong answer, James will be deducted by 2 mark(s). If James scored 68 marks in total, how many questions did James answer correctly?

36

42

37

33

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume James answered all the 77 questions correctly, and each correct answer has 4 marks, then James should score 308 marks,
\begin{array}{rcl}
77\times4=308.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since James only scored 68 marks, therefore James totally lost
\begin{array}{rcl}
308-68=240.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
240\div6=40.
\end{array}
The number of correct answers is
\begin{array}{rcl}
77-40=37.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 77, we have,
\begin{array}{rcl}
C+W=77.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=68.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=154.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=222.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&222\div6\\
&=&37.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&77-37\\
&=&40.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume James answered all the 77 questions correctly, and each correct answer has 4 marks, then James should score 308 marks,
\begin{array}{rcl}
77\times4=308.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since James only scored 68 marks, therefore James totally lost
\begin{array}{rcl}
308-68=240.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
240\div6=40.
\end{array}
The number of correct answers is
\begin{array}{rcl}
77-40=37.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 77, we have,
\begin{array}{rcl}
C+W=77.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=68.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=154.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=222.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&222\div6\\
&=&37.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&77-37\\
&=&40.\tag{6}
\end{array}

Mason attended a Chinese Multiple Choices Test. Mason answered all 63 questions. For each correct answer, Mason will get 4 marks. However, for each wrong answer, Mason will be deducted by 1 mark(s). If Mason scored 52 marks in total, how many questions did Mason answer wrongly?

35

42

41

40

Sorry. Please check the correct answer below.

You are Right

__Method 1: Method of Assumption__

Assume Mason answered all the 63 questions correctly, and each correct answer has 4 marks, then Mason should score 252 marks,
\begin{array}{rcl}
63\times4=252.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Mason only scored 52 marks, therefore Mason totally lost
\begin{array}{rcl}
252-52=200.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
200\div5=40.
\end{array}
The number of correct answers is
\begin{array}{rcl}
63-40=23.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 63, we have,
\begin{array}{rcl}
C+W=63.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=52.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=115.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&115\div5\\
&=&23.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&63-23\\
&=&40.\tag{6}
\end{array}

James attended a South-East Asia Maths Olympaid (SEAMO). James answered all 34 questions. For each correct answer, James will get 6 marks. However, for each wrong answer, James will be deducted by 2 mark(s). If James scored 108 marks in total, how many questions did James answer wrongly?

11

18

12

22

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume James answered all the 34 questions correctly, and each correct answer has 6 marks, then James should score 204 marks,
\begin{array}{rcl}
34\times6=204.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since James only scored 108 marks, therefore James totally lost
\begin{array}{rcl}
204-108=96.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
96\div8=12.
\end{array}
The number of correct answers is
\begin{array}{rcl}
34-12=22.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 34, we have,
\begin{array}{rcl}
C+W=34.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=108.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=68.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=176.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&176\div8\\
&=&22.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&34-22\\
&=&12.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume James answered all the 34 questions correctly, and each correct answer has 6 marks, then James should score 204 marks,
\begin{array}{rcl}
34\times6=204.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since James only scored 108 marks, therefore James totally lost
\begin{array}{rcl}
204-108=96.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
96\div8=12.
\end{array}
The number of correct answers is
\begin{array}{rcl}
34-12=22.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 34, we have,
\begin{array}{rcl}
C+W=34.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=108.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=68.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=176.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&176\div8\\
&=&22.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&34-22\\
&=&12.\tag{6}
\end{array}

William attended a Maths Competition. William answered all 50 questions. For each correct answer, William will get 5 marks. However, for each wrong answer, William will be deducted by 1 mark(s). If William scored 100 marks in total, how many questions did William answer wrongly?

23

31

24

25

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume William answered all the 50 questions correctly, and each correct answer has 5 marks, then William should score 250 marks,
\begin{array}{rcl}
50\times5=250.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since William only scored 100 marks, therefore William totally lost
\begin{array}{rcl}
250-100=150.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
150\div6=25.
\end{array}
The number of correct answers is
\begin{array}{rcl}
50-25=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 50, we have,
\begin{array}{rcl}
C+W=50.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=100.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=150.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&150\div6\\
&=&25.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&50-25\\
&=&25.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume William answered all the 50 questions correctly, and each correct answer has 5 marks, then William should score 250 marks,
\begin{array}{rcl}
50\times5=250.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since William only scored 100 marks, therefore William totally lost
\begin{array}{rcl}
250-100=150.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
150\div6=25.
\end{array}
The number of correct answers is
\begin{array}{rcl}
50-25=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 50, we have,
\begin{array}{rcl}
C+W=50.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=100.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=150.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&150\div6\\
&=&25.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&50-25\\
&=&25.\tag{6}
\end{array}

William attended a Australian Maths Trust (AMT). William answered all 22 questions. For each correct answer, William will get 6 marks. However, for each wrong answer, William will be deducted by 2 mark(s). If William scored 84 marks in total, how many questions did William answer wrongly?

18

1

6

15

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume William answered all the 22 questions correctly, and each correct answer has 6 marks, then William should score 132 marks,
\begin{array}{rcl}
22\times6=132.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since William only scored 84 marks, therefore William totally lost
\begin{array}{rcl}
132-84=48.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
48\div8=6.
\end{array}
The number of correct answers is
\begin{array}{rcl}
22-6=16.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 22, we have,
\begin{array}{rcl}
C+W=22.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=84.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=44.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=128.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&128\div8\\
&=&16.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&22-16\\
&=&6.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume William answered all the 22 questions correctly, and each correct answer has 6 marks, then William should score 132 marks,
\begin{array}{rcl}
22\times6=132.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since William only scored 84 marks, therefore William totally lost
\begin{array}{rcl}
132-84=48.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
48\div8=6.
\end{array}
The number of correct answers is
\begin{array}{rcl}
22-6=16.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 22, we have,
\begin{array}{rcl}
C+W=22.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=84.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=44.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=128.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&128\div8\\
&=&16.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&22-16\\
&=&6.\tag{6}
\end{array}

James attended a Australian Maths Trust (AMT). James answered all 23 questions. For each correct answer, James will get 3 marks. However, for each wrong answer, James will be deducted by 1 mark(s). If James scored 45 marks in total, how many questions did James answer wrongly?

17

6

5

12

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume James answered all the 23 questions correctly, and each correct answer has 3 marks, then James should score 69 marks,
\begin{array}{rcl}
23\times3=69.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since James only scored 45 marks, therefore James totally lost
\begin{array}{rcl}
69-45=24.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
24\div4=6.
\end{array}
The number of correct answers is
\begin{array}{rcl}
23-6=17.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 23, we have,
\begin{array}{rcl}
C+W=23.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=45.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=68.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&68\div4\\
&=&17.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&23-17\\
&=&6.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume James answered all the 23 questions correctly, and each correct answer has 3 marks, then James should score 69 marks,
\begin{array}{rcl}
23\times3=69.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since James only scored 45 marks, therefore James totally lost
\begin{array}{rcl}
69-45=24.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
24\div4=6.
\end{array}
The number of correct answers is
\begin{array}{rcl}
23-6=17.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 23, we have,
\begin{array}{rcl}
C+W=23.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=45.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=68.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&68\div4\\
&=&17.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&23-17\\
&=&6.\tag{6}
\end{array}

Larry Page attended a South-East Asia Maths Olympaid (SEAMO). Larry Page answered all 12 questions. For each correct answer, Larry Page will get 3 marks. However, for each wrong answer, Larry Page will be deducted by 1 mark(s). If Larry Page scored 36 marks in total, how many questions did Larry Page answer correctly?

20

11

12

10

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Larry Page answered all the 12 questions correctly, and each correct answer has 3 marks, then Larry Page should score 36 marks,
\begin{array}{rcl}
12\times3=36.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since Larry Page only scored 36 marks, therefore Larry Page totally lost
\begin{array}{rcl}
36-36=0.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
0\div4=0.
\end{array}
The number of correct answers is
\begin{array}{rcl}
12-0=12.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 12, we have,
\begin{array}{rcl}
C+W=12.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=36.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=48.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&48\div4\\
&=&12.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&12-12\\
&=&0.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Larry Page answered all the 12 questions correctly, and each correct answer has 3 marks, then Larry Page should score 36 marks,
\begin{array}{rcl}
12\times3=36.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since Larry Page only scored 36 marks, therefore Larry Page totally lost
\begin{array}{rcl}
36-36=0.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
0\div4=0.
\end{array}
The number of correct answers is
\begin{array}{rcl}
12-0=12.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 12, we have,
\begin{array}{rcl}
C+W=12.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=36.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=48.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&48\div4\\
&=&12.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&12-12\\
&=&0.\tag{6}
\end{array}

Isabella attended a South-East Asia Maths Olympaid (SEAMO). Isabella answered all 69 questions. For each correct answer, Isabella will get 4 marks. However, for each wrong answer, Isabella will be deducted by 1 mark(s). If Isabella scored 76 marks in total, how many questions did Isabella answer correctly?

30

29

33

28

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Isabella answered all the 69 questions correctly, and each correct answer has 4 marks, then Isabella should score 276 marks,
\begin{array}{rcl}
69\times4=276.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Isabella only scored 76 marks, therefore Isabella totally lost
\begin{array}{rcl}
276-76=200.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
200\div5=40.
\end{array}
The number of correct answers is
\begin{array}{rcl}
69-40=29.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 69, we have,
\begin{array}{rcl}
C+W=69.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=76.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=145.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&145\div5\\
&=&29.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&69-29\\
&=&40.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Isabella answered all the 69 questions correctly, and each correct answer has 4 marks, then Isabella should score 276 marks,
\begin{array}{rcl}
69\times4=276.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Isabella only scored 76 marks, therefore Isabella totally lost
\begin{array}{rcl}
276-76=200.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
200\div5=40.
\end{array}
The number of correct answers is
\begin{array}{rcl}
69-40=29.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 69, we have,
\begin{array}{rcl}
C+W=69.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=76.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=145.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&145\div5\\
&=&29.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&69-29\\
&=&40.\tag{6}
\end{array}

Benjamin attended a Maths Competition. Benjamin answered all 103 questions. For each correct answer, Benjamin will get 10 marks. However, for each wrong answer, Benjamin will be deducted by 2 mark(s). If Benjamin scored 190 marks in total, how many questions did Benjamin answer wrongly?

66

69

70

71

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Benjamin answered all the 103 questions correctly, and each correct answer has 10 marks, then Benjamin should score 1030 marks,
\begin{array}{rcl}
103\times10=1030.
\end{array}
For every question Benjamin answered wrongly, Benjamin will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Benjamin only scored 190 marks, therefore Benjamin totally lost
\begin{array}{rcl}
1030-190=840.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
840\div12=70.
\end{array}
The number of correct answers is
\begin{array}{rcl}
103-70=33.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 103, we have,
\begin{array}{rcl}
C+W=103.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=190.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=206.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=396.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&396\div12\\
&=&33.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&103-33\\
&=&70.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Benjamin answered all the 103 questions correctly, and each correct answer has 10 marks, then Benjamin should score 1030 marks,
\begin{array}{rcl}
103\times10=1030.
\end{array}
For every question Benjamin answered wrongly, Benjamin will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Benjamin only scored 190 marks, therefore Benjamin totally lost
\begin{array}{rcl}
1030-190=840.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
840\div12=70.
\end{array}
The number of correct answers is
\begin{array}{rcl}
103-70=33.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 103, we have,
\begin{array}{rcl}
C+W=103.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=190.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=206.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=396.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&396\div12\\
&=&33.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&103-33\\
&=&70.\tag{6}
\end{array}

Emma attended a Singapore Maths Olympaid (SMO). Emma answered all 55 questions. For each correct answer, Emma will get 4 marks. However, for each wrong answer, Emma will be deducted by 2 mark(s). If Emma scored 76 marks in total, how many questions did Emma answer correctly?

30

31

34

28

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Emma answered all the 55 questions correctly, and each correct answer has 4 marks, then Emma should score 220 marks,
\begin{array}{rcl}
55\times4=220.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Emma only scored 76 marks, therefore Emma totally lost
\begin{array}{rcl}
220-76=144.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
144\div6=24.
\end{array}
The number of correct answers is
\begin{array}{rcl}
55-24=31.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 55, we have,
\begin{array}{rcl}
C+W=55.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=76.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=110.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=186.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&186\div6\\
&=&31.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&55-31\\
&=&24.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Emma answered all the 55 questions correctly, and each correct answer has 4 marks, then Emma should score 220 marks,
\begin{array}{rcl}
55\times4=220.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Emma only scored 76 marks, therefore Emma totally lost
\begin{array}{rcl}
220-76=144.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
144\div6=24.
\end{array}
The number of correct answers is
\begin{array}{rcl}
55-24=31.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 55, we have,
\begin{array}{rcl}
C+W=55.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=76.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=110.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=186.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&186\div6\\
&=&31.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&55-31\\
&=&24.\tag{6}
\end{array}

Jacob attended a American Maths Olympiad (AMO). Jacob answered all 35 questions. For each correct answer, Jacob will get 2 marks. However, for each wrong answer, Jacob will be deducted by 1 mark(s). If Jacob scored 40 marks in total, how many questions did Jacob answer correctly?

31

20

27

25

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Jacob answered all the 35 questions correctly, and each correct answer has 2 marks, then Jacob should score 70 marks,
\begin{array}{rcl}
35\times2=70.
\end{array}
For every question Jacob answered wrongly, Jacob will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Jacob only scored 40 marks, therefore Jacob totally lost
\begin{array}{rcl}
70-40=30.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
30\div3=10.
\end{array}
The number of correct answers is
\begin{array}{rcl}
35-10=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 35, we have,
\begin{array}{rcl}
C+W=35.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=40.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=75.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&75\div3\\
&=&25.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&35-25\\
&=&10.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Jacob answered all the 35 questions correctly, and each correct answer has 2 marks, then Jacob should score 70 marks,
\begin{array}{rcl}
35\times2=70.
\end{array}
For every question Jacob answered wrongly, Jacob will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Jacob only scored 40 marks, therefore Jacob totally lost
\begin{array}{rcl}
70-40=30.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
30\div3=10.
\end{array}
The number of correct answers is
\begin{array}{rcl}
35-10=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 35, we have,
\begin{array}{rcl}
C+W=35.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=40.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=75.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&75\div3\\
&=&25.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&35-25\\
&=&10.\tag{6}
\end{array}

Isabella attended a American Maths Olympiad (AMO). Isabella answered all 115 questions. For each correct answer, Isabella will get 10 marks. However, for each wrong answer, Isabella will be deducted by 2 mark(s). If Isabella scored 190 marks in total, how many questions did Isabella answer correctly?

35

37

40

33

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Isabella answered all the 115 questions correctly, and each correct answer has 10 marks, then Isabella should score 1150 marks,
\begin{array}{rcl}
115\times10=1150.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Isabella only scored 190 marks, therefore Isabella totally lost
\begin{array}{rcl}
1150-190=960.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
960\div12=80.
\end{array}
The number of correct answers is
\begin{array}{rcl}
115-80=35.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 115, we have,
\begin{array}{rcl}
C+W=115.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=190.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=230.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=420.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&420\div12\\
&=&35.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&115-35\\
&=&80.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Isabella answered all the 115 questions correctly, and each correct answer has 10 marks, then Isabella should score 1150 marks,
\begin{array}{rcl}
115\times10=1150.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Isabella only scored 190 marks, therefore Isabella totally lost
\begin{array}{rcl}
1150-190=960.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
960\div12=80.
\end{array}
The number of correct answers is
\begin{array}{rcl}
115-80=35.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 115, we have,
\begin{array}{rcl}
C+W=115.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=190.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=230.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=420.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&420\div12\\
&=&35.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&115-35\\
&=&80.\tag{6}
\end{array}

Mason attended a Australian Maths Trust (AMT). Mason answered all 63 questions. For each correct answer, Mason will get 6 marks. However, for each wrong answer, Mason will be deducted by 2 mark(s). If Mason scored 90 marks in total, how many questions did Mason answer wrongly?

36

29

26

37

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Mason answered all the 63 questions correctly, and each correct answer has 6 marks, then Mason should score 378 marks,
\begin{array}{rcl}
63\times6=378.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since Mason only scored 90 marks, therefore Mason totally lost
\begin{array}{rcl}
378-90=288.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
288\div8=36.
\end{array}
The number of correct answers is
\begin{array}{rcl}
63-36=27.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 63, we have,
\begin{array}{rcl}
C+W=63.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=90.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=126.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=216.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&216\div8\\
&=&27.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&63-27\\
&=&36.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Mason answered all the 63 questions correctly, and each correct answer has 6 marks, then Mason should score 378 marks,
\begin{array}{rcl}
63\times6=378.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since Mason only scored 90 marks, therefore Mason totally lost
\begin{array}{rcl}
378-90=288.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
288\div8=36.
\end{array}
The number of correct answers is
\begin{array}{rcl}
63-36=27.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 63, we have,
\begin{array}{rcl}
C+W=63.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=90.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=126.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=216.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&216\div8\\
&=&27.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&63-27\\
&=&36.\tag{6}
\end{array}

Olivia attended a American Maths Olympiad (AMO). Olivia answered all 47 questions. For each correct answer, Olivia will get 2 marks. However, for each wrong answer, Olivia will be deducted by 1 mark(s). If Olivia scored 34 marks in total, how many questions did Olivia answer correctly?

27

22

32

23

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Olivia answered all the 47 questions correctly, and each correct answer has 2 marks, then Olivia should score 94 marks,
\begin{array}{rcl}
47\times2=94.
\end{array}
For every question Olivia answered wrongly, Olivia will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Olivia only scored 34 marks, therefore Olivia totally lost
\begin{array}{rcl}
94-34=60.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
60\div3=20.
\end{array}
The number of correct answers is
\begin{array}{rcl}
47-20=27.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 47, we have,
\begin{array}{rcl}
C+W=47.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=34.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=81.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&81\div3\\
&=&27.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&47-27\\
&=&20.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Olivia answered all the 47 questions correctly, and each correct answer has 2 marks, then Olivia should score 94 marks,
\begin{array}{rcl}
47\times2=94.
\end{array}
For every question Olivia answered wrongly, Olivia will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Olivia only scored 34 marks, therefore Olivia totally lost
\begin{array}{rcl}
94-34=60.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
60\div3=20.
\end{array}
The number of correct answers is
\begin{array}{rcl}
47-20=27.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 47, we have,
\begin{array}{rcl}
C+W=47.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=34.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=81.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&81\div3\\
&=&27.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&47-27\\
&=&20.\tag{6}
\end{array}

Ava attended a Australian Maths Trust (AMT). Ava answered all 20 questions. For each correct answer, Ava will get 6 marks. However, for each wrong answer, Ava will be deducted by 2 mark(s). If Ava scored 120 marks in total, how many questions did Ava answer correctly?

23

26

16

20

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Ava answered all the 20 questions correctly, and each correct answer has 6 marks, then Ava should score 120 marks,
\begin{array}{rcl}
20\times6=120.
\end{array}
For every question Ava answered wrongly, Ava will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since Ava only scored 120 marks, therefore Ava totally lost
\begin{array}{rcl}
120-120=0.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
0\div8=0.
\end{array}
The number of correct answers is
\begin{array}{rcl}
20-0=20.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 20, we have,
\begin{array}{rcl}
C+W=20.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=120.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=40.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=160.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&160\div8\\
&=&20.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&20-20\\
&=&0.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Ava answered all the 20 questions correctly, and each correct answer has 6 marks, then Ava should score 120 marks,
\begin{array}{rcl}
20\times6=120.
\end{array}
For every question Ava answered wrongly, Ava will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since Ava only scored 120 marks, therefore Ava totally lost
\begin{array}{rcl}
120-120=0.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
0\div8=0.
\end{array}
The number of correct answers is
\begin{array}{rcl}
20-0=20.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 20, we have,
\begin{array}{rcl}
C+W=20.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=120.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=40.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=160.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&160\div8\\
&=&20.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&20-20\\
&=&0.\tag{6}
\end{array}

Sophia attended a Australian Maths Trust (AMT). Sophia answered all 19 questions. For each correct answer, Sophia will get 5 marks. However, for each wrong answer, Sophia will be deducted by 1 mark(s). If Sophia scored 65 marks in total, how many questions did Sophia answer correctly?

14

12

20

18

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Sophia answered all the 19 questions correctly, and each correct answer has 5 marks, then Sophia should score 95 marks,
\begin{array}{rcl}
19\times5=95.
\end{array}
For every question Sophia answered wrongly, Sophia will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since Sophia only scored 65 marks, therefore Sophia totally lost
\begin{array}{rcl}
95-65=30.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
30\div6=5.
\end{array}
The number of correct answers is
\begin{array}{rcl}
19-5=14.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 19, we have,
\begin{array}{rcl}
C+W=19.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=65.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=84.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&84\div6\\
&=&14.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&19-14\\
&=&5.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Sophia answered all the 19 questions correctly, and each correct answer has 5 marks, then Sophia should score 95 marks,
\begin{array}{rcl}
19\times5=95.
\end{array}
For every question Sophia answered wrongly, Sophia will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since Sophia only scored 65 marks, therefore Sophia totally lost
\begin{array}{rcl}
95-65=30.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
30\div6=5.
\end{array}
The number of correct answers is
\begin{array}{rcl}
19-5=14.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 19, we have,
\begin{array}{rcl}
C+W=19.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=65.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=84.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&84\div6\\
&=&14.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&19-14\\
&=&5.\tag{6}
\end{array}

William attended a Maths Competition. William answered all 46 questions. For each correct answer, William will get 4 marks. However, for each wrong answer, William will be deducted by 2 mark(s). If William scored 40 marks in total, how many questions did William answer correctly?

22

21

24

17

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume William answered all the 46 questions correctly, and each correct answer has 4 marks, then William should score 184 marks,
\begin{array}{rcl}
46\times4=184.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since William only scored 40 marks, therefore William totally lost
\begin{array}{rcl}
184-40=144.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
144\div6=24.
\end{array}
The number of correct answers is
\begin{array}{rcl}
46-24=22.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 46, we have,
\begin{array}{rcl}
C+W=46.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=40.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=92.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=132.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&132\div6\\
&=&22.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&46-22\\
&=&24.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume William answered all the 46 questions correctly, and each correct answer has 4 marks, then William should score 184 marks,
\begin{array}{rcl}
46\times4=184.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since William only scored 40 marks, therefore William totally lost
\begin{array}{rcl}
184-40=144.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
144\div6=24.
\end{array}
The number of correct answers is
\begin{array}{rcl}
46-24=22.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 46, we have,
\begin{array}{rcl}
C+W=46.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=40.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=92.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=132.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&132\div6\\
&=&22.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&46-22\\
&=&24.\tag{6}
\end{array}

Noah attended a South-East Asia Maths Olympaid (SEAMO). Noah answered all 24 questions. For each correct answer, Noah will get 5 marks. However, for each wrong answer, Noah will be deducted by 1 mark(s). If Noah scored 60 marks in total, how many questions did Noah answer wrongly?

15

5

10

6

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Noah answered all the 24 questions correctly, and each correct answer has 5 marks, then Noah should score 120 marks,
\begin{array}{rcl}
24\times5=120.
\end{array}
For every question Noah answered wrongly, Noah will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since Noah only scored 60 marks, therefore Noah totally lost
\begin{array}{rcl}
120-60=60.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
60\div6=10.
\end{array}
The number of correct answers is
\begin{array}{rcl}
24-10=14.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 24, we have,
\begin{array}{rcl}
C+W=24.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=60.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=84.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&84\div6\\
&=&14.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&24-14\\
&=&10.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Noah answered all the 24 questions correctly, and each correct answer has 5 marks, then Noah should score 120 marks,
\begin{array}{rcl}
24\times5=120.
\end{array}
For every question Noah answered wrongly, Noah will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since Noah only scored 60 marks, therefore Noah totally lost
\begin{array}{rcl}
120-60=60.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
60\div6=10.
\end{array}
The number of correct answers is
\begin{array}{rcl}
24-10=14.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 24, we have,
\begin{array}{rcl}
C+W=24.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=60.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=84.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&84\div6\\
&=&14.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&24-14\\
&=&10.\tag{6}
\end{array}

Mason attended a English Spelling Bee Competition. Mason answered all 63 questions. For each correct answer, Mason will get 4 marks. However, for each wrong answer, Mason will be deducted by 2 mark(s). If Mason scored 60 marks in total, how many questions did Mason answer correctly?

34

27

31

32

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Mason answered all the 63 questions correctly, and each correct answer has 4 marks, then Mason should score 252 marks,
\begin{array}{rcl}
63\times4=252.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Mason only scored 60 marks, therefore Mason totally lost
\begin{array}{rcl}
252-60=192.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
192\div6=32.
\end{array}
The number of correct answers is
\begin{array}{rcl}
63-32=31.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 63, we have,
\begin{array}{rcl}
C+W=63.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=60.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=126.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=186.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&186\div6\\
&=&31.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&63-31\\
&=&32.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Mason answered all the 63 questions correctly, and each correct answer has 4 marks, then Mason should score 252 marks,
\begin{array}{rcl}
63\times4=252.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Mason only scored 60 marks, therefore Mason totally lost
\begin{array}{rcl}
252-60=192.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
192\div6=32.
\end{array}
The number of correct answers is
\begin{array}{rcl}
63-32=31.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 63, we have,
\begin{array}{rcl}
C+W=63.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=60.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=126.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=186.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&186\div6\\
&=&31.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&63-31\\
&=&32.\tag{6}
\end{array}

Mason attended a Maths Competition. Mason answered all 40 questions. For each correct answer, Mason will get 2 marks. However, for each wrong answer, Mason will be deducted by 1 mark(s). If Mason scored 32 marks in total, how many questions did Mason answer correctly?

24

29

26

19

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Mason answered all the 40 questions correctly, and each correct answer has 2 marks, then Mason should score 80 marks,
\begin{array}{rcl}
40\times2=80.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Mason only scored 32 marks, therefore Mason totally lost
\begin{array}{rcl}
80-32=48.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
48\div3=16.
\end{array}
The number of correct answers is
\begin{array}{rcl}
40-16=24.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 40, we have,
\begin{array}{rcl}
C+W=40.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=32.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=72.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&72\div3\\
&=&24.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&40-24\\
&=&16.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Mason answered all the 40 questions correctly, and each correct answer has 2 marks, then Mason should score 80 marks,
\begin{array}{rcl}
40\times2=80.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Mason only scored 32 marks, therefore Mason totally lost
\begin{array}{rcl}
80-32=48.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
48\div3=16.
\end{array}
The number of correct answers is
\begin{array}{rcl}
40-16=24.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 40, we have,
\begin{array}{rcl}
C+W=40.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=32.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=72.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&72\div3\\
&=&24.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&40-24\\
&=&16.\tag{6}
\end{array}

James attended a Chinese Multiple Choices Test. James answered all 65 questions. For each correct answer, James will get 6 marks. However, for each wrong answer, James will be deducted by 2 mark(s). If James scored 102 marks in total, how many questions did James answer correctly?

26

28

29

24

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume James answered all the 65 questions correctly, and each correct answer has 6 marks, then James should score 390 marks,
\begin{array}{rcl}
65\times6=390.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since James only scored 102 marks, therefore James totally lost
\begin{array}{rcl}
390-102=288.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
288\div8=36.
\end{array}
The number of correct answers is
\begin{array}{rcl}
65-36=29.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 65, we have,
\begin{array}{rcl}
C+W=65.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=102.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=130.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=232.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&232\div8\\
&=&29.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&65-29\\
&=&36.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume James answered all the 65 questions correctly, and each correct answer has 6 marks, then James should score 390 marks,
\begin{array}{rcl}
65\times6=390.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since James only scored 102 marks, therefore James totally lost
\begin{array}{rcl}
390-102=288.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
288\div8=36.
\end{array}
The number of correct answers is
\begin{array}{rcl}
65-36=29.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 65, we have,
\begin{array}{rcl}
C+W=65.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=102.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=130.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=232.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&232\div8\\
&=&29.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&65-29\\
&=&36.\tag{6}
\end{array}

Isabella attended a South-East Asia Maths Olympaid (SEAMO). Isabella answered all 11 questions. For each correct answer, Isabella will get 3 marks. However, for each wrong answer, Isabella will be deducted by 1 mark(s). If Isabella scored 33 marks in total, how many questions did Isabella answer correctly?

9

11

13

15

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Isabella answered all the 11 questions correctly, and each correct answer has 3 marks, then Isabella should score 33 marks,
\begin{array}{rcl}
11\times3=33.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since Isabella only scored 33 marks, therefore Isabella totally lost
\begin{array}{rcl}
33-33=0.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
0\div4=0.
\end{array}
The number of correct answers is
\begin{array}{rcl}
11-0=11.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 11, we have,
\begin{array}{rcl}
C+W=11.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=33.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=44.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&44\div4\\
&=&11.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&11-11\\
&=&0.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Isabella answered all the 11 questions correctly, and each correct answer has 3 marks, then Isabella should score 33 marks,
\begin{array}{rcl}
11\times3=33.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since Isabella only scored 33 marks, therefore Isabella totally lost
\begin{array}{rcl}
33-33=0.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
0\div4=0.
\end{array}
The number of correct answers is
\begin{array}{rcl}
11-0=11.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 11, we have,
\begin{array}{rcl}
C+W=11.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=33.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=44.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&44\div4\\
&=&11.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&11-11\\
&=&0.\tag{6}
\end{array}

Noah attended a Singapore Maths Olympaid (SMO). Noah answered all 30 questions. For each correct answer, Noah will get 8 marks. However, for each wrong answer, Noah will be deducted by 2 mark(s). If Noah scored 80 marks in total, how many questions did Noah answer correctly?

20

14

18

10

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Noah answered all the 30 questions correctly, and each correct answer has 8 marks, then Noah should score 240 marks,
\begin{array}{rcl}
30\times8=240.
\end{array}
For every question Noah answered wrongly, Noah will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Noah only scored 80 marks, therefore Noah totally lost
\begin{array}{rcl}
240-80=160.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
160\div10=16.
\end{array}
The number of correct answers is
\begin{array}{rcl}
30-16=14.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 30, we have,
\begin{array}{rcl}
C+W=30.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=80.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=60.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=140.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&140\div10\\
&=&14.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&30-14\\
&=&16.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Noah answered all the 30 questions correctly, and each correct answer has 8 marks, then Noah should score 240 marks,
\begin{array}{rcl}
30\times8=240.
\end{array}
For every question Noah answered wrongly, Noah will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Noah only scored 80 marks, therefore Noah totally lost
\begin{array}{rcl}
240-80=160.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
160\div10=16.
\end{array}
The number of correct answers is
\begin{array}{rcl}
30-16=14.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 30, we have,
\begin{array}{rcl}
C+W=30.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=80.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=60.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=140.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&140\div10\\
&=&14.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&30-14\\
&=&16.\tag{6}
\end{array}

Jacob attended a English Spelling Bee Competition. Jacob answered all 48 questions. For each correct answer, Jacob will get 3 marks. However, for each wrong answer, Jacob will be deducted by 1 mark(s). If Jacob scored 60 marks in total, how many questions did Jacob answer wrongly?

17

16

20

21

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Jacob answered all the 48 questions correctly, and each correct answer has 3 marks, then Jacob should score 144 marks,
\begin{array}{rcl}
48\times3=144.
\end{array}
For every question Jacob answered wrongly, Jacob will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since Jacob only scored 60 marks, therefore Jacob totally lost
\begin{array}{rcl}
144-60=84.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
84\div4=21.
\end{array}
The number of correct answers is
\begin{array}{rcl}
48-21=27.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 48, we have,
\begin{array}{rcl}
C+W=48.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=60.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=108.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&108\div4\\
&=&27.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&48-27\\
&=&21.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Jacob answered all the 48 questions correctly, and each correct answer has 3 marks, then Jacob should score 144 marks,
\begin{array}{rcl}
48\times3=144.
\end{array}
For every question Jacob answered wrongly, Jacob will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since Jacob only scored 60 marks, therefore Jacob totally lost
\begin{array}{rcl}
144-60=84.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
84\div4=21.
\end{array}
The number of correct answers is
\begin{array}{rcl}
48-21=27.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 48, we have,
\begin{array}{rcl}
C+W=48.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=60.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=108.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&108\div4\\
&=&27.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&48-27\\
&=&21.\tag{6}
\end{array}

Benjamin attended a American Maths Olympiad (AMO). Benjamin answered all 72 questions. For each correct answer, Benjamin will get 10 marks. However, for each wrong answer, Benjamin will be deducted by 2 mark(s). If Benjamin scored 120 marks in total, how many questions did Benjamin answer wrongly?

46

45

50

49

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Benjamin answered all the 72 questions correctly, and each correct answer has 10 marks, then Benjamin should score 720 marks,
\begin{array}{rcl}
72\times10=720.
\end{array}
For every question Benjamin answered wrongly, Benjamin will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Benjamin only scored 120 marks, therefore Benjamin totally lost
\begin{array}{rcl}
720-120=600.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
600\div12=50.
\end{array}
The number of correct answers is
\begin{array}{rcl}
72-50=22.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 72, we have,
\begin{array}{rcl}
C+W=72.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=120.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=144.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=264.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&264\div12\\
&=&22.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&72-22\\
&=&50.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Benjamin answered all the 72 questions correctly, and each correct answer has 10 marks, then Benjamin should score 720 marks,
\begin{array}{rcl}
72\times10=720.
\end{array}
For every question Benjamin answered wrongly, Benjamin will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Benjamin only scored 120 marks, therefore Benjamin totally lost
\begin{array}{rcl}
720-120=600.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
600\div12=50.
\end{array}
The number of correct answers is
\begin{array}{rcl}
72-50=22.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 72, we have,
\begin{array}{rcl}
C+W=72.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=120.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=144.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=264.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&264\div12\\
&=&22.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&72-22\\
&=&50.\tag{6}
\end{array}

Emma attended a South-East Asia Maths Olympaid (SEAMO). Emma answered all 48 questions. For each correct answer, Emma will get 4 marks. However, for each wrong answer, Emma will be deducted by 2 mark(s). If Emma scored 72 marks in total, how many questions did Emma answer correctly?

33

32

28

27

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Emma answered all the 48 questions correctly, and each correct answer has 4 marks, then Emma should score 192 marks,
\begin{array}{rcl}
48\times4=192.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Emma only scored 72 marks, therefore Emma totally lost
\begin{array}{rcl}
192-72=120.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
120\div6=20.
\end{array}
The number of correct answers is
\begin{array}{rcl}
48-20=28.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 48, we have,
\begin{array}{rcl}
C+W=48.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=72.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=96.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=168.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&168\div6\\
&=&28.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&48-28\\
&=&20.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Emma answered all the 48 questions correctly, and each correct answer has 4 marks, then Emma should score 192 marks,
\begin{array}{rcl}
48\times4=192.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Emma only scored 72 marks, therefore Emma totally lost
\begin{array}{rcl}
192-72=120.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
120\div6=20.
\end{array}
The number of correct answers is
\begin{array}{rcl}
48-20=28.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 48, we have,
\begin{array}{rcl}
C+W=48.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=72.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=96.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=168.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&168\div6\\
&=&28.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&48-28\\
&=&20.\tag{6}
\end{array}

Sophia attended a English Spelling Bee Competition. Sophia answered all 28 questions. For each correct answer, Sophia will get 2 marks. However, for each wrong answer, Sophia will be deducted by 1 mark(s). If Sophia scored 26 marks in total, how many questions did Sophia answer correctly?

18

26

20

13

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Sophia answered all the 28 questions correctly, and each correct answer has 2 marks, then Sophia should score 56 marks,
\begin{array}{rcl}
28\times2=56.
\end{array}
For every question Sophia answered wrongly, Sophia will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Sophia only scored 26 marks, therefore Sophia totally lost
\begin{array}{rcl}
56-26=30.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
30\div3=10.
\end{array}
The number of correct answers is
\begin{array}{rcl}
28-10=18.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 28, we have,
\begin{array}{rcl}
C+W=28.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=26.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=54.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&54\div3\\
&=&18.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&28-18\\
&=&10.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Sophia answered all the 28 questions correctly, and each correct answer has 2 marks, then Sophia should score 56 marks,
\begin{array}{rcl}
28\times2=56.
\end{array}
For every question Sophia answered wrongly, Sophia will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Sophia only scored 26 marks, therefore Sophia totally lost
\begin{array}{rcl}
56-26=30.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
30\div3=10.
\end{array}
The number of correct answers is
\begin{array}{rcl}
28-10=18.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 28, we have,
\begin{array}{rcl}
C+W=28.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=26.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=54.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&54\div3\\
&=&18.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&28-18\\
&=&10.\tag{6}
\end{array}

Emma attended a Chinese Multiple Choices Test. Emma answered all 49 questions. For each correct answer, Emma will get 4 marks. However, for each wrong answer, Emma will be deducted by 2 mark(s). If Emma scored 52 marks in total, how many questions did Emma answer wrongly?

30

24

25

20

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Emma answered all the 49 questions correctly, and each correct answer has 4 marks, then Emma should score 196 marks,
\begin{array}{rcl}
49\times4=196.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Emma only scored 52 marks, therefore Emma totally lost
\begin{array}{rcl}
196-52=144.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
144\div6=24.
\end{array}
The number of correct answers is
\begin{array}{rcl}
49-24=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 49, we have,
\begin{array}{rcl}
C+W=49.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=52.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=98.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=150.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&150\div6\\
&=&25.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&49-25\\
&=&24.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Emma answered all the 49 questions correctly, and each correct answer has 4 marks, then Emma should score 196 marks,
\begin{array}{rcl}
49\times4=196.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Emma only scored 52 marks, therefore Emma totally lost
\begin{array}{rcl}
196-52=144.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
144\div6=24.
\end{array}
The number of correct answers is
\begin{array}{rcl}
49-24=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 49, we have,
\begin{array}{rcl}
C+W=49.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=52.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=98.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=150.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&150\div6\\
&=&25.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&49-25\\
&=&24.\tag{6}
\end{array}

Isabella attended a English Spelling Bee Competition. Isabella answered all 16 questions. For each correct answer, Isabella will get 4 marks. However, for each wrong answer, Isabella will be deducted by 2 mark(s). If Isabella scored 40 marks in total, how many questions did Isabella answer correctly?

8

16

14

12

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Isabella answered all the 16 questions correctly, and each correct answer has 4 marks, then Isabella should score 64 marks,
\begin{array}{rcl}
16\times4=64.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Isabella only scored 40 marks, therefore Isabella totally lost
\begin{array}{rcl}
64-40=24.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
24\div6=4.
\end{array}
The number of correct answers is
\begin{array}{rcl}
16-4=12.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 16, we have,
\begin{array}{rcl}
C+W=16.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=40.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=32.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=72.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&72\div6\\
&=&12.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&16-12\\
&=&4.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Isabella answered all the 16 questions correctly, and each correct answer has 4 marks, then Isabella should score 64 marks,
\begin{array}{rcl}
16\times4=64.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Isabella only scored 40 marks, therefore Isabella totally lost
\begin{array}{rcl}
64-40=24.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
24\div6=4.
\end{array}
The number of correct answers is
\begin{array}{rcl}
16-4=12.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 16, we have,
\begin{array}{rcl}
C+W=16.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=40.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=32.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=72.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&72\div6\\
&=&12.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&16-12\\
&=&4.\tag{6}
\end{array}

Sophia attended a English Spelling Bee Competition. Sophia answered all 132 questions. For each correct answer, Sophia will get 10 marks. However, for each wrong answer, Sophia will be deducted by 2 mark(s). If Sophia scored 120 marks in total, how many questions did Sophia answer wrongly?

100

101

102

106

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Sophia answered all the 132 questions correctly, and each correct answer has 10 marks, then Sophia should score 1320 marks,
\begin{array}{rcl}
132\times10=1320.
\end{array}
For every question Sophia answered wrongly, Sophia will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Sophia only scored 120 marks, therefore Sophia totally lost
\begin{array}{rcl}
1320-120=1200.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
1200\div12=100.
\end{array}
The number of correct answers is
\begin{array}{rcl}
132-100=32.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 132, we have,
\begin{array}{rcl}
C+W=132.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=120.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=264.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=384.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&384\div12\\
&=&32.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&132-32\\
&=&100.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Sophia answered all the 132 questions correctly, and each correct answer has 10 marks, then Sophia should score 1320 marks,
\begin{array}{rcl}
132\times10=1320.
\end{array}
For every question Sophia answered wrongly, Sophia will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Sophia only scored 120 marks, therefore Sophia totally lost
\begin{array}{rcl}
1320-120=1200.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
1200\div12=100.
\end{array}
The number of correct answers is
\begin{array}{rcl}
132-100=32.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 132, we have,
\begin{array}{rcl}
C+W=132.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=120.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=264.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=384.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&384\div12\\
&=&32.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&132-32\\
&=&100.\tag{6}
\end{array}

Larry Page attended a South-East Asia Maths Olympaid (SEAMO). Larry Page answered all 16 questions. For each correct answer, Larry Page will get 8 marks. However, for each wrong answer, Larry Page will be deducted by 2 mark(s). If Larry Page scored 128 marks in total, how many questions did Larry Page answer correctly?

18

16

14

21

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Larry Page answered all the 16 questions correctly, and each correct answer has 8 marks, then Larry Page should score 128 marks,
\begin{array}{rcl}
16\times8=128.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Larry Page only scored 128 marks, therefore Larry Page totally lost
\begin{array}{rcl}
128-128=0.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
0\div10=0.
\end{array}
The number of correct answers is
\begin{array}{rcl}
16-0=16.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 16, we have,
\begin{array}{rcl}
C+W=16.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=128.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=32.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=160.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&160\div10\\
&=&16.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&16-16\\
&=&0.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Larry Page answered all the 16 questions correctly, and each correct answer has 8 marks, then Larry Page should score 128 marks,
\begin{array}{rcl}
16\times8=128.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Larry Page only scored 128 marks, therefore Larry Page totally lost
\begin{array}{rcl}
128-128=0.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
0\div10=0.
\end{array}
The number of correct answers is
\begin{array}{rcl}
16-0=16.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 16, we have,
\begin{array}{rcl}
C+W=16.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=128.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=32.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=160.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&160\div10\\
&=&16.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&16-16\\
&=&0.\tag{6}
\end{array}

Olivia attended a South-East Asia Maths Olympaid (SEAMO). Olivia answered all 26 questions. For each correct answer, Olivia will get 3 marks. However, for each wrong answer, Olivia will be deducted by 1 mark(s). If Olivia scored 54 marks in total, how many questions did Olivia answer correctly?

15

17

24

20

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Olivia answered all the 26 questions correctly, and each correct answer has 3 marks, then Olivia should score 78 marks,
\begin{array}{rcl}
26\times3=78.
\end{array}
For every question Olivia answered wrongly, Olivia will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since Olivia only scored 54 marks, therefore Olivia totally lost
\begin{array}{rcl}
78-54=24.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
24\div4=6.
\end{array}
The number of correct answers is
\begin{array}{rcl}
26-6=20.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 26, we have,
\begin{array}{rcl}
C+W=26.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=54.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=80.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&80\div4\\
&=&20.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&26-20\\
&=&6.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Olivia answered all the 26 questions correctly, and each correct answer has 3 marks, then Olivia should score 78 marks,
\begin{array}{rcl}
26\times3=78.
\end{array}
For every question Olivia answered wrongly, Olivia will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since Olivia only scored 54 marks, therefore Olivia totally lost
\begin{array}{rcl}
78-54=24.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
24\div4=6.
\end{array}
The number of correct answers is
\begin{array}{rcl}
26-6=20.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 26, we have,
\begin{array}{rcl}
C+W=26.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=54.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=80.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&80\div4\\
&=&20.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&26-20\\
&=&6.\tag{6}
\end{array}

Mason attended a Maths Competition. Mason answered all 92 questions. For each correct answer, Mason will get 6 marks. However, for each wrong answer, Mason will be deducted by 2 mark(s). If Mason scored 72 marks in total, how many questions did Mason answer correctly?

35

40

36

32

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Mason answered all the 92 questions correctly, and each correct answer has 6 marks, then Mason should score 552 marks,
\begin{array}{rcl}
92\times6=552.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since Mason only scored 72 marks, therefore Mason totally lost
\begin{array}{rcl}
552-72=480.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
480\div8=60.
\end{array}
The number of correct answers is
\begin{array}{rcl}
92-60=32.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 92, we have,
\begin{array}{rcl}
C+W=92.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=72.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=184.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=256.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&256\div8\\
&=&32.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&92-32\\
&=&60.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Mason answered all the 92 questions correctly, and each correct answer has 6 marks, then Mason should score 552 marks,
\begin{array}{rcl}
92\times6=552.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since Mason only scored 72 marks, therefore Mason totally lost
\begin{array}{rcl}
552-72=480.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
480\div8=60.
\end{array}
The number of correct answers is
\begin{array}{rcl}
92-60=32.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 92, we have,
\begin{array}{rcl}
C+W=92.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=72.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=184.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=256.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&256\div8\\
&=&32.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&92-32\\
&=&60.\tag{6}
\end{array}

Bill Gates attended a South-East Asia Maths Olympaid (SEAMO). Bill Gates answered all 17 questions. For each correct answer, Bill Gates will get 4 marks. However, for each wrong answer, Bill Gates will be deducted by 1 mark(s). If Bill Gates scored 48 marks in total, how many questions did Bill Gates answer wrongly?

11

12

3

4

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Bill Gates answered all the 17 questions correctly, and each correct answer has 4 marks, then Bill Gates should score 68 marks,
\begin{array}{rcl}
17\times4=68.
\end{array}
For every question Bill Gates answered wrongly, Bill Gates will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Bill Gates only scored 48 marks, therefore Bill Gates totally lost
\begin{array}{rcl}
68-48=20.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
20\div5=4.
\end{array}
The number of correct answers is
\begin{array}{rcl}
17-4=13.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 17, we have,
\begin{array}{rcl}
C+W=17.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=48.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=65.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&65\div5\\
&=&13.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&17-13\\
&=&4.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Bill Gates answered all the 17 questions correctly, and each correct answer has 4 marks, then Bill Gates should score 68 marks,
\begin{array}{rcl}
17\times4=68.
\end{array}
For every question Bill Gates answered wrongly, Bill Gates will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Bill Gates only scored 48 marks, therefore Bill Gates totally lost
\begin{array}{rcl}
68-48=20.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
20\div5=4.
\end{array}
The number of correct answers is
\begin{array}{rcl}
17-4=13.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 17, we have,
\begin{array}{rcl}
C+W=17.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=48.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=65.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&65\div5\\
&=&13.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&17-13\\
&=&4.\tag{6}
\end{array}

Jacob attended a Maths Competition. Jacob answered all 108 questions. For each correct answer, Jacob will get 8 marks. However, for each wrong answer, Jacob will be deducted by 2 mark(s). If Jacob scored 144 marks in total, how many questions did Jacob answer wrongly?

73

36

67

72

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Jacob answered all the 108 questions correctly, and each correct answer has 8 marks, then Jacob should score 864 marks,
\begin{array}{rcl}
108\times8=864.
\end{array}
For every question Jacob answered wrongly, Jacob will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Jacob only scored 144 marks, therefore Jacob totally lost
\begin{array}{rcl}
864-144=720.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
720\div10=72.
\end{array}
The number of correct answers is
\begin{array}{rcl}
108-72=36.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 108, we have,
\begin{array}{rcl}
C+W=108.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=144.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=216.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=360.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&360\div10\\
&=&36.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&108-36\\
&=&72.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Jacob answered all the 108 questions correctly, and each correct answer has 8 marks, then Jacob should score 864 marks,
\begin{array}{rcl}
108\times8=864.
\end{array}
For every question Jacob answered wrongly, Jacob will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Jacob only scored 144 marks, therefore Jacob totally lost
\begin{array}{rcl}
864-144=720.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
720\div10=72.
\end{array}
The number of correct answers is
\begin{array}{rcl}
108-72=36.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 108, we have,
\begin{array}{rcl}
C+W=108.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=144.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=216.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=360.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&360\div10\\
&=&36.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&108-36\\
&=&72.\tag{6}
\end{array}

Isabella attended a Singapore Maths Olympaid (SMO). Isabella answered all 111 questions. For each correct answer, Isabella will get 8 marks. However, for each wrong answer, Isabella will be deducted by 2 mark(s). If Isabella scored 88 marks in total, how many questions did Isabella answer wrongly?

31

33

80

32

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Isabella answered all the 111 questions correctly, and each correct answer has 8 marks, then Isabella should score 888 marks,
\begin{array}{rcl}
111\times8=888.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Isabella only scored 88 marks, therefore Isabella totally lost
\begin{array}{rcl}
888-88=800.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
800\div10=80.
\end{array}
The number of correct answers is
\begin{array}{rcl}
111-80=31.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 111, we have,
\begin{array}{rcl}
C+W=111.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=88.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=222.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=310.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&310\div10\\
&=&31.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&111-31\\
&=&80.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Isabella answered all the 111 questions correctly, and each correct answer has 8 marks, then Isabella should score 888 marks,
\begin{array}{rcl}
111\times8=888.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Isabella only scored 88 marks, therefore Isabella totally lost
\begin{array}{rcl}
888-88=800.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
800\div10=80.
\end{array}
The number of correct answers is
\begin{array}{rcl}
111-80=31.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 111, we have,
\begin{array}{rcl}
C+W=111.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=88.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=222.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=310.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&310\div10\\
&=&31.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&111-31\\
&=&80.\tag{6}
\end{array}

Larry Page attended a Australian Maths Trust (AMT). Larry Page answered all 81 questions. For each correct answer, Larry Page will get 8 marks. However, for each wrong answer, Larry Page will be deducted by 2 mark(s). If Larry Page scored 88 marks in total, how many questions did Larry Page answer wrongly?

56

23

57

55

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Larry Page answered all the 81 questions correctly, and each correct answer has 8 marks, then Larry Page should score 648 marks,
\begin{array}{rcl}
81\times8=648.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Larry Page only scored 88 marks, therefore Larry Page totally lost
\begin{array}{rcl}
648-88=560.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
560\div10=56.
\end{array}
The number of correct answers is
\begin{array}{rcl}
81-56=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 81, we have,
\begin{array}{rcl}
C+W=81.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=88.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=162.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=250.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&250\div10\\
&=&25.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&81-25\\
&=&56.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Larry Page answered all the 81 questions correctly, and each correct answer has 8 marks, then Larry Page should score 648 marks,
\begin{array}{rcl}
81\times8=648.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Larry Page only scored 88 marks, therefore Larry Page totally lost
\begin{array}{rcl}
648-88=560.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
560\div10=56.
\end{array}
The number of correct answers is
\begin{array}{rcl}
81-56=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 81, we have,
\begin{array}{rcl}
C+W=81.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=88.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=162.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=250.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&250\div10\\
&=&25.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&81-25\\
&=&56.\tag{6}
\end{array}

Olivia attended a Maths Competition. Olivia answered all 18 questions. For each correct answer, Olivia will get 5 marks. However, for each wrong answer, Olivia will be deducted by 1 mark(s). If Olivia scored 60 marks in total, how many questions did Olivia answer wrongly?

14

13

5

6

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Olivia answered all the 18 questions correctly, and each correct answer has 5 marks, then Olivia should score 90 marks,
\begin{array}{rcl}
18\times5=90.
\end{array}
For every question Olivia answered wrongly, Olivia will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since Olivia only scored 60 marks, therefore Olivia totally lost
\begin{array}{rcl}
90-60=30.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
30\div6=5.
\end{array}
The number of correct answers is
\begin{array}{rcl}
18-5=13.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 18, we have,
\begin{array}{rcl}
C+W=18.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=60.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=78.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&78\div6\\
&=&13.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&18-13\\
&=&5.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Olivia answered all the 18 questions correctly, and each correct answer has 5 marks, then Olivia should score 90 marks,
\begin{array}{rcl}
18\times5=90.
\end{array}
For every question Olivia answered wrongly, Olivia will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since Olivia only scored 60 marks, therefore Olivia totally lost
\begin{array}{rcl}
90-60=30.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
30\div6=5.
\end{array}
The number of correct answers is
\begin{array}{rcl}
18-5=13.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 18, we have,
\begin{array}{rcl}
C+W=18.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=60.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=78.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&78\div6\\
&=&13.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&18-13\\
&=&5.\tag{6}
\end{array}

Mason attended a Singapore Maths Olympaid (SMO). Mason answered all 102 questions. For each correct answer, Mason will get 10 marks. However, for each wrong answer, Mason will be deducted by 2 mark(s). If Mason scored 180 marks in total, how many questions did Mason answer correctly?

32

33

36

31

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Mason answered all the 102 questions correctly, and each correct answer has 10 marks, then Mason should score 1020 marks,
\begin{array}{rcl}
102\times10=1020.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Mason only scored 180 marks, therefore Mason totally lost
\begin{array}{rcl}
1020-180=840.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
840\div12=70.
\end{array}
The number of correct answers is
\begin{array}{rcl}
102-70=32.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 102, we have,
\begin{array}{rcl}
C+W=102.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=180.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=204.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=384.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&384\div12\\
&=&32.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&102-32\\
&=&70.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Mason answered all the 102 questions correctly, and each correct answer has 10 marks, then Mason should score 1020 marks,
\begin{array}{rcl}
102\times10=1020.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Mason only scored 180 marks, therefore Mason totally lost
\begin{array}{rcl}
1020-180=840.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
840\div12=70.
\end{array}
The number of correct answers is
\begin{array}{rcl}
102-70=32.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 102, we have,
\begin{array}{rcl}
C+W=102.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=180.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=204.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=384.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&384\div12\\
&=&32.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&102-32\\
&=&70.\tag{6}
\end{array}

Larry Page attended a English Spelling Bee Competition. Larry Page answered all 67 questions. For each correct answer, Larry Page will get 4 marks. However, for each wrong answer, Larry Page will be deducted by 2 mark(s). If Larry Page scored 52 marks in total, how many questions did Larry Page answer wrongly?

29

30

36

37

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Larry Page answered all the 67 questions correctly, and each correct answer has 4 marks, then Larry Page should score 268 marks,
\begin{array}{rcl}
67\times4=268.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Larry Page only scored 52 marks, therefore Larry Page totally lost
\begin{array}{rcl}
268-52=216.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
216\div6=36.
\end{array}
The number of correct answers is
\begin{array}{rcl}
67-36=31.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 67, we have,
\begin{array}{rcl}
C+W=67.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=52.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=134.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=186.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&186\div6\\
&=&31.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&67-31\\
&=&36.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Larry Page answered all the 67 questions correctly, and each correct answer has 4 marks, then Larry Page should score 268 marks,
\begin{array}{rcl}
67\times4=268.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Larry Page only scored 52 marks, therefore Larry Page totally lost
\begin{array}{rcl}
268-52=216.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
216\div6=36.
\end{array}
The number of correct answers is
\begin{array}{rcl}
67-36=31.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 67, we have,
\begin{array}{rcl}
C+W=67.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=52.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=134.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=186.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&186\div6\\
&=&31.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&67-31\\
&=&36.\tag{6}
\end{array}

Larry Page attended a Maths Competition. Larry Page answered all 31 questions. For each correct answer, Larry Page will get 2 marks. However, for each wrong answer, Larry Page will be deducted by 1 mark(s). If Larry Page scored 26 marks in total, how many questions did Larry Page answer wrongly?

20

12

8

14

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Larry Page answered all the 31 questions correctly, and each correct answer has 2 marks, then Larry Page should score 62 marks,
\begin{array}{rcl}
31\times2=62.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Larry Page only scored 26 marks, therefore Larry Page totally lost
\begin{array}{rcl}
62-26=36.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
36\div3=12.
\end{array}
The number of correct answers is
\begin{array}{rcl}
31-12=19.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 31, we have,
\begin{array}{rcl}
C+W=31.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=26.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=57.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&57\div3\\
&=&19.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&31-19\\
&=&12.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Larry Page answered all the 31 questions correctly, and each correct answer has 2 marks, then Larry Page should score 62 marks,
\begin{array}{rcl}
31\times2=62.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Larry Page only scored 26 marks, therefore Larry Page totally lost
\begin{array}{rcl}
62-26=36.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
36\div3=12.
\end{array}
The number of correct answers is
\begin{array}{rcl}
31-12=19.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 31, we have,
\begin{array}{rcl}
C+W=31.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=26.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=57.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&57\div3\\
&=&19.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&31-19\\
&=&12.\tag{6}
\end{array}

William attended a American Maths Olympiad (AMO). William answered all 51 questions. For each correct answer, William will get 4 marks. However, for each wrong answer, William will be deducted by 2 mark(s). If William scored 60 marks in total, how many questions did William answer correctly?

31

29

27

33

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume William answered all the 51 questions correctly, and each correct answer has 4 marks, then William should score 204 marks,
\begin{array}{rcl}
51\times4=204.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since William only scored 60 marks, therefore William totally lost
\begin{array}{rcl}
204-60=144.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
144\div6=24.
\end{array}
The number of correct answers is
\begin{array}{rcl}
51-24=27.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 51, we have,
\begin{array}{rcl}
C+W=51.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=60.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=102.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=162.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&162\div6\\
&=&27.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&51-27\\
&=&24.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume William answered all the 51 questions correctly, and each correct answer has 4 marks, then William should score 204 marks,
\begin{array}{rcl}
51\times4=204.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since William only scored 60 marks, therefore William totally lost
\begin{array}{rcl}
204-60=144.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
144\div6=24.
\end{array}
The number of correct answers is
\begin{array}{rcl}
51-24=27.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 51, we have,
\begin{array}{rcl}
C+W=51.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=60.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=102.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=162.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&162\div6\\
&=&27.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&51-27\\
&=&24.\tag{6}
\end{array}

Larry Page attended a South-East Asia Maths Olympaid (SEAMO). Larry Page answered all 67 questions. For each correct answer, Larry Page will get 4 marks. However, for each wrong answer, Larry Page will be deducted by 2 mark(s). If Larry Page scored 76 marks in total, how many questions did Larry Page answer correctly?

38

32

35

40

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Larry Page answered all the 67 questions correctly, and each correct answer has 4 marks, then Larry Page should score 268 marks,
\begin{array}{rcl}
67\times4=268.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Larry Page only scored 76 marks, therefore Larry Page totally lost
\begin{array}{rcl}
268-76=192.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
192\div6=32.
\end{array}
The number of correct answers is
\begin{array}{rcl}
67-32=35.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 67, we have,
\begin{array}{rcl}
C+W=67.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=76.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=134.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=210.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&210\div6\\
&=&35.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&67-35\\
&=&32.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Larry Page answered all the 67 questions correctly, and each correct answer has 4 marks, then Larry Page should score 268 marks,
\begin{array}{rcl}
67\times4=268.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Larry Page only scored 76 marks, therefore Larry Page totally lost
\begin{array}{rcl}
268-76=192.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
192\div6=32.
\end{array}
The number of correct answers is
\begin{array}{rcl}
67-32=35.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 67, we have,
\begin{array}{rcl}
C+W=67.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=76.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=134.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=210.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&210\div6\\
&=&35.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&67-35\\
&=&32.\tag{6}
\end{array}

Emma attended a Australian Maths Trust (AMT). Emma answered all 48 questions. For each correct answer, Emma will get 4 marks. However, for each wrong answer, Emma will be deducted by 1 mark(s). If Emma scored 72 marks in total, how many questions did Emma answer wrongly?

25

19

24

20

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Emma answered all the 48 questions correctly, and each correct answer has 4 marks, then Emma should score 192 marks,
\begin{array}{rcl}
48\times4=192.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Emma only scored 72 marks, therefore Emma totally lost
\begin{array}{rcl}
192-72=120.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
120\div5=24.
\end{array}
The number of correct answers is
\begin{array}{rcl}
48-24=24.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 48, we have,
\begin{array}{rcl}
C+W=48.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=72.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=120.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&120\div5\\
&=&24.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&48-24\\
&=&24.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Emma answered all the 48 questions correctly, and each correct answer has 4 marks, then Emma should score 192 marks,
\begin{array}{rcl}
48\times4=192.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Emma only scored 72 marks, therefore Emma totally lost
\begin{array}{rcl}
192-72=120.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
120\div5=24.
\end{array}
The number of correct answers is
\begin{array}{rcl}
48-24=24.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 48, we have,
\begin{array}{rcl}
C+W=48.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=72.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=120.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&120\div5\\
&=&24.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&48-24\\
&=&24.\tag{6}
\end{array}

James attended a South-East Asia Maths Olympaid (SEAMO). James answered all 67 questions. For each correct answer, James will get 5 marks. However, for each wrong answer, James will be deducted by 1 mark(s). If James scored 95 marks in total, how many questions did James answer wrongly?

40

42

25

35

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume James answered all the 67 questions correctly, and each correct answer has 5 marks, then James should score 335 marks,
\begin{array}{rcl}
67\times5=335.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since James only scored 95 marks, therefore James totally lost
\begin{array}{rcl}
335-95=240.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
240\div6=40.
\end{array}
The number of correct answers is
\begin{array}{rcl}
67-40=27.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 67, we have,
\begin{array}{rcl}
C+W=67.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=95.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=162.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&162\div6\\
&=&27.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&67-27\\
&=&40.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume James answered all the 67 questions correctly, and each correct answer has 5 marks, then James should score 335 marks,
\begin{array}{rcl}
67\times5=335.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since James only scored 95 marks, therefore James totally lost
\begin{array}{rcl}
335-95=240.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
240\div6=40.
\end{array}
The number of correct answers is
\begin{array}{rcl}
67-40=27.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 67, we have,
\begin{array}{rcl}
C+W=67.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=95.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=162.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&162\div6\\
&=&27.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&67-27\\
&=&40.\tag{6}
\end{array}

Bill Gates attended a South-East Asia Maths Olympaid (SEAMO). Bill Gates answered all 23 questions. For each correct answer, Bill Gates will get 2 marks. However, for each wrong answer, Bill Gates will be deducted by 1 mark(s). If Bill Gates scored 22 marks in total, how many questions did Bill Gates answer correctly?

18

15

13

12

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Bill Gates answered all the 23 questions correctly, and each correct answer has 2 marks, then Bill Gates should score 46 marks,
\begin{array}{rcl}
23\times2=46.
\end{array}
For every question Bill Gates answered wrongly, Bill Gates will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Bill Gates only scored 22 marks, therefore Bill Gates totally lost
\begin{array}{rcl}
46-22=24.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
24\div3=8.
\end{array}
The number of correct answers is
\begin{array}{rcl}
23-8=15.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 23, we have,
\begin{array}{rcl}
C+W=23.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=22.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=45.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&45\div3\\
&=&15.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&23-15\\
&=&8.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Bill Gates answered all the 23 questions correctly, and each correct answer has 2 marks, then Bill Gates should score 46 marks,
\begin{array}{rcl}
23\times2=46.
\end{array}
For every question Bill Gates answered wrongly, Bill Gates will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Bill Gates only scored 22 marks, therefore Bill Gates totally lost
\begin{array}{rcl}
46-22=24.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
24\div3=8.
\end{array}
The number of correct answers is
\begin{array}{rcl}
23-8=15.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 23, we have,
\begin{array}{rcl}
C+W=23.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=22.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=45.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&45\div3\\
&=&15.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&23-15\\
&=&8.\tag{6}
\end{array}

Liam attended a Australian Maths Trust (AMT). Liam answered all 50 questions. For each correct answer, Liam will get 4 marks. However, for each wrong answer, Liam will be deducted by 1 mark(s). If Liam scored 60 marks in total, how many questions did Liam answer wrongly?

20

28

23

36

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Liam answered all the 50 questions correctly, and each correct answer has 4 marks, then Liam should score 200 marks,
\begin{array}{rcl}
50\times4=200.
\end{array}
For every question Liam answered wrongly, Liam will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Liam only scored 60 marks, therefore Liam totally lost
\begin{array}{rcl}
200-60=140.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
140\div5=28.
\end{array}
The number of correct answers is
\begin{array}{rcl}
50-28=22.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 50, we have,
\begin{array}{rcl}
C+W=50.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=60.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=110.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&110\div5\\
&=&22.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&50-22\\
&=&28.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Liam answered all the 50 questions correctly, and each correct answer has 4 marks, then Liam should score 200 marks,
\begin{array}{rcl}
50\times4=200.
\end{array}
For every question Liam answered wrongly, Liam will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Liam only scored 60 marks, therefore Liam totally lost
\begin{array}{rcl}
200-60=140.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
140\div5=28.
\end{array}
The number of correct answers is
\begin{array}{rcl}
50-28=22.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 50, we have,
\begin{array}{rcl}
C+W=50.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=60.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=110.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&110\div5\\
&=&22.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&50-22\\
&=&28.\tag{6}
\end{array}

Bill Gates attended a South-East Asia Maths Olympaid (SEAMO). Bill Gates answered all 26 questions. For each correct answer, Bill Gates will get 3 marks. However, for each wrong answer, Bill Gates will be deducted by 1 mark(s). If Bill Gates scored 42 marks in total, how many questions did Bill Gates answer correctly?

17

20

14

15

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Bill Gates answered all the 26 questions correctly, and each correct answer has 3 marks, then Bill Gates should score 78 marks,
\begin{array}{rcl}
26\times3=78.
\end{array}
For every question Bill Gates answered wrongly, Bill Gates will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since Bill Gates only scored 42 marks, therefore Bill Gates totally lost
\begin{array}{rcl}
78-42=36.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
36\div4=9.
\end{array}
The number of correct answers is
\begin{array}{rcl}
26-9=17.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 26, we have,
\begin{array}{rcl}
C+W=26.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=42.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=68.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&68\div4\\
&=&17.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&26-17\\
&=&9.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Bill Gates answered all the 26 questions correctly, and each correct answer has 3 marks, then Bill Gates should score 78 marks,
\begin{array}{rcl}
26\times3=78.
\end{array}
For every question Bill Gates answered wrongly, Bill Gates will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since Bill Gates only scored 42 marks, therefore Bill Gates totally lost
\begin{array}{rcl}
78-42=36.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
36\div4=9.
\end{array}
The number of correct answers is
\begin{array}{rcl}
26-9=17.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 26, we have,
\begin{array}{rcl}
C+W=26.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=42.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=68.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&68\div4\\
&=&17.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&26-17\\
&=&9.\tag{6}
\end{array}

Benjamin attended a Maths Competition. Benjamin answered all 35 questions. For each correct answer, Benjamin will get 8 marks. However, for each wrong answer, Benjamin will be deducted by 2 mark(s). If Benjamin scored 120 marks in total, how many questions did Benjamin answer correctly?

25

16

19

23

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Benjamin answered all the 35 questions correctly, and each correct answer has 8 marks, then Benjamin should score 280 marks,
\begin{array}{rcl}
35\times8=280.
\end{array}
For every question Benjamin answered wrongly, Benjamin will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Benjamin only scored 120 marks, therefore Benjamin totally lost
\begin{array}{rcl}
280-120=160.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
160\div10=16.
\end{array}
The number of correct answers is
\begin{array}{rcl}
35-16=19.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 35, we have,
\begin{array}{rcl}
C+W=35.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=120.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=70.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=190.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&190\div10\\
&=&19.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&35-19\\
&=&16.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Benjamin answered all the 35 questions correctly, and each correct answer has 8 marks, then Benjamin should score 280 marks,
\begin{array}{rcl}
35\times8=280.
\end{array}
For every question Benjamin answered wrongly, Benjamin will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Benjamin only scored 120 marks, therefore Benjamin totally lost
\begin{array}{rcl}
280-120=160.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
160\div10=16.
\end{array}
The number of correct answers is
\begin{array}{rcl}
35-16=19.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 35, we have,
\begin{array}{rcl}
C+W=35.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=120.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=70.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=190.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&190\div10\\
&=&19.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&35-19\\
&=&16.\tag{6}
\end{array}

Mason attended a English Spelling Bee Competition. Mason answered all 41 questions. For each correct answer, Mason will get 2 marks. However, for each wrong answer, Mason will be deducted by 1 mark(s). If Mason scored 34 marks in total, how many questions did Mason answer correctly?

25

23

33

22

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Mason answered all the 41 questions correctly, and each correct answer has 2 marks, then Mason should score 82 marks,
\begin{array}{rcl}
41\times2=82.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Mason only scored 34 marks, therefore Mason totally lost
\begin{array}{rcl}
82-34=48.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
48\div3=16.
\end{array}
The number of correct answers is
\begin{array}{rcl}
41-16=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 41, we have,
\begin{array}{rcl}
C+W=41.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=34.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=75.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&75\div3\\
&=&25.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&41-25\\
&=&16.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Mason answered all the 41 questions correctly, and each correct answer has 2 marks, then Mason should score 82 marks,
\begin{array}{rcl}
41\times2=82.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Mason only scored 34 marks, therefore Mason totally lost
\begin{array}{rcl}
82-34=48.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
48\div3=16.
\end{array}
The number of correct answers is
\begin{array}{rcl}
41-16=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 41, we have,
\begin{array}{rcl}
C+W=41.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=34.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=75.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&75\div3\\
&=&25.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&41-25\\
&=&16.\tag{6}
\end{array}

James attended a Chinese Multiple Choices Test. James answered all 66 questions. For each correct answer, James will get 5 marks. However, for each wrong answer, James will be deducted by 1 mark(s). If James scored 60 marks in total, how many questions did James answer wrongly?

45

22

41

19

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume James answered all the 66 questions correctly, and each correct answer has 5 marks, then James should score 330 marks,
\begin{array}{rcl}
66\times5=330.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since James only scored 60 marks, therefore James totally lost
\begin{array}{rcl}
330-60=270.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
270\div6=45.
\end{array}
The number of correct answers is
\begin{array}{rcl}
66-45=21.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 66, we have,
\begin{array}{rcl}
C+W=66.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=60.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=126.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&126\div6\\
&=&21.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&66-21\\
&=&45.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume James answered all the 66 questions correctly, and each correct answer has 5 marks, then James should score 330 marks,
\begin{array}{rcl}
66\times5=330.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since James only scored 60 marks, therefore James totally lost
\begin{array}{rcl}
330-60=270.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
270\div6=45.
\end{array}
The number of correct answers is
\begin{array}{rcl}
66-45=21.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 66, we have,
\begin{array}{rcl}
C+W=66.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=60.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=126.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&126\div6\\
&=&21.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&66-21\\
&=&45.\tag{6}
\end{array}

Liam attended a Singapore Maths Olympaid (SMO). Liam answered all 30 questions. For each correct answer, Liam will get 5 marks. However, for each wrong answer, Liam will be deducted by 1 mark(s). If Liam scored 90 marks in total, how many questions did Liam answer correctly?

19

28

21

20

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Liam answered all the 30 questions correctly, and each correct answer has 5 marks, then Liam should score 150 marks,
\begin{array}{rcl}
30\times5=150.
\end{array}
For every question Liam answered wrongly, Liam will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since Liam only scored 90 marks, therefore Liam totally lost
\begin{array}{rcl}
150-90=60.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
60\div6=10.
\end{array}
The number of correct answers is
\begin{array}{rcl}
30-10=20.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 30, we have,
\begin{array}{rcl}
C+W=30.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=90.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=120.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&120\div6\\
&=&20.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&30-20\\
&=&10.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Liam answered all the 30 questions correctly, and each correct answer has 5 marks, then Liam should score 150 marks,
\begin{array}{rcl}
30\times5=150.
\end{array}
For every question Liam answered wrongly, Liam will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since Liam only scored 90 marks, therefore Liam totally lost
\begin{array}{rcl}
150-90=60.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
60\div6=10.
\end{array}
The number of correct answers is
\begin{array}{rcl}
30-10=20.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 30, we have,
\begin{array}{rcl}
C+W=30.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=90.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=120.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&120\div6\\
&=&20.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&30-20\\
&=&10.\tag{6}
\end{array}

William attended a Chinese Multiple Choices Test. William answered all 101 questions. For each correct answer, William will get 8 marks. However, for each wrong answer, William will be deducted by 2 mark(s). If William scored 88 marks in total, how many questions did William answer wrongly?

72

67

74

78

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume William answered all the 101 questions correctly, and each correct answer has 8 marks, then William should score 808 marks,
\begin{array}{rcl}
101\times8=808.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since William only scored 88 marks, therefore William totally lost
\begin{array}{rcl}
808-88=720.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
720\div10=72.
\end{array}
The number of correct answers is
\begin{array}{rcl}
101-72=29.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 101, we have,
\begin{array}{rcl}
C+W=101.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=88.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=202.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=290.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&290\div10\\
&=&29.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&101-29\\
&=&72.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume William answered all the 101 questions correctly, and each correct answer has 8 marks, then William should score 808 marks,
\begin{array}{rcl}
101\times8=808.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since William only scored 88 marks, therefore William totally lost
\begin{array}{rcl}
808-88=720.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
720\div10=72.
\end{array}
The number of correct answers is
\begin{array}{rcl}
101-72=29.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 101, we have,
\begin{array}{rcl}
C+W=101.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=88.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=202.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=290.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&290\div10\\
&=&29.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&101-29\\
&=&72.\tag{6}
\end{array}

Olivia attended a South-East Asia Maths Olympaid (SEAMO). Olivia answered all 71 questions. For each correct answer, Olivia will get 4 marks. However, for each wrong answer, Olivia will be deducted by 2 mark(s). If Olivia scored 44 marks in total, how many questions did Olivia answer correctly?

33

26

31

39

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Olivia answered all the 71 questions correctly, and each correct answer has 4 marks, then Olivia should score 284 marks,
\begin{array}{rcl}
71\times4=284.
\end{array}
For every question Olivia answered wrongly, Olivia will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Olivia only scored 44 marks, therefore Olivia totally lost
\begin{array}{rcl}
284-44=240.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
240\div6=40.
\end{array}
The number of correct answers is
\begin{array}{rcl}
71-40=31.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 71, we have,
\begin{array}{rcl}
C+W=71.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=44.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=142.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=186.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&186\div6\\
&=&31.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&71-31\\
&=&40.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Olivia answered all the 71 questions correctly, and each correct answer has 4 marks, then Olivia should score 284 marks,
\begin{array}{rcl}
71\times4=284.
\end{array}
For every question Olivia answered wrongly, Olivia will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Olivia only scored 44 marks, therefore Olivia totally lost
\begin{array}{rcl}
284-44=240.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
240\div6=40.
\end{array}
The number of correct answers is
\begin{array}{rcl}
71-40=31.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 71, we have,
\begin{array}{rcl}
C+W=71.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=44.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=142.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=186.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&186\div6\\
&=&31.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&71-31\\
&=&40.\tag{6}
\end{array}

Larry Page attended a Chinese Multiple Choices Test. Larry Page answered all 59 questions. For each correct answer, Larry Page will get 4 marks. However, for each wrong answer, Larry Page will be deducted by 2 mark(s). If Larry Page scored 44 marks in total, how many questions did Larry Page answer correctly?

32

27

35

24

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Larry Page answered all the 59 questions correctly, and each correct answer has 4 marks, then Larry Page should score 236 marks,
\begin{array}{rcl}
59\times4=236.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Larry Page only scored 44 marks, therefore Larry Page totally lost
\begin{array}{rcl}
236-44=192.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
192\div6=32.
\end{array}
The number of correct answers is
\begin{array}{rcl}
59-32=27.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 59, we have,
\begin{array}{rcl}
C+W=59.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=44.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=118.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=162.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&162\div6\\
&=&27.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&59-27\\
&=&32.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Larry Page answered all the 59 questions correctly, and each correct answer has 4 marks, then Larry Page should score 236 marks,
\begin{array}{rcl}
59\times4=236.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Larry Page only scored 44 marks, therefore Larry Page totally lost
\begin{array}{rcl}
236-44=192.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
192\div6=32.
\end{array}
The number of correct answers is
\begin{array}{rcl}
59-32=27.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 59, we have,
\begin{array}{rcl}
C+W=59.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=44.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=118.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=162.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&162\div6\\
&=&27.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&59-27\\
&=&32.\tag{6}
\end{array}

Emma attended a Maths Competition. Emma answered all 60 questions. For each correct answer, Emma will get 4 marks. However, for each wrong answer, Emma will be deducted by 1 mark(s). If Emma scored 80 marks in total, how many questions did Emma answer correctly?

36

28

24

32

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Emma answered all the 60 questions correctly, and each correct answer has 4 marks, then Emma should score 240 marks,
\begin{array}{rcl}
60\times4=240.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Emma only scored 80 marks, therefore Emma totally lost
\begin{array}{rcl}
240-80=160.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
160\div5=32.
\end{array}
The number of correct answers is
\begin{array}{rcl}
60-32=28.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 60, we have,
\begin{array}{rcl}
C+W=60.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=80.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=140.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&140\div5\\
&=&28.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&60-28\\
&=&32.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Emma answered all the 60 questions correctly, and each correct answer has 4 marks, then Emma should score 240 marks,
\begin{array}{rcl}
60\times4=240.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Emma only scored 80 marks, therefore Emma totally lost
\begin{array}{rcl}
240-80=160.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
160\div5=32.
\end{array}
The number of correct answers is
\begin{array}{rcl}
60-32=28.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 60, we have,
\begin{array}{rcl}
C+W=60.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=80.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=140.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&140\div5\\
&=&28.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&60-28\\
&=&32.\tag{6}
\end{array}

Sophia attended a Singapore Maths Olympaid (SMO). Sophia answered all 57 questions. For each correct answer, Sophia will get 4 marks. However, for each wrong answer, Sophia will be deducted by 1 mark(s). If Sophia scored 48 marks in total, how many questions did Sophia answer correctly?

23

21

19

16

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Sophia answered all the 57 questions correctly, and each correct answer has 4 marks, then Sophia should score 228 marks,
\begin{array}{rcl}
57\times4=228.
\end{array}
For every question Sophia answered wrongly, Sophia will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Sophia only scored 48 marks, therefore Sophia totally lost
\begin{array}{rcl}
228-48=180.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
180\div5=36.
\end{array}
The number of correct answers is
\begin{array}{rcl}
57-36=21.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 57, we have,
\begin{array}{rcl}
C+W=57.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=48.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=105.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&105\div5\\
&=&21.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&57-21\\
&=&36.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Sophia answered all the 57 questions correctly, and each correct answer has 4 marks, then Sophia should score 228 marks,
\begin{array}{rcl}
57\times4=228.
\end{array}
For every question Sophia answered wrongly, Sophia will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Sophia only scored 48 marks, therefore Sophia totally lost
\begin{array}{rcl}
228-48=180.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
180\div5=36.
\end{array}
The number of correct answers is
\begin{array}{rcl}
57-36=21.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 57, we have,
\begin{array}{rcl}
C+W=57.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=48.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=105.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&105\div5\\
&=&21.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&57-21\\
&=&36.\tag{6}
\end{array}

Liam attended a American Maths Olympiad (AMO). Liam answered all 12 questions. For each correct answer, Liam will get 2 marks. However, for each wrong answer, Liam will be deducted by 1 mark(s). If Liam scored 24 marks in total, how many questions did Liam answer correctly?

12

9

16

11

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Liam answered all the 12 questions correctly, and each correct answer has 2 marks, then Liam should score 24 marks,
\begin{array}{rcl}
12\times2=24.
\end{array}
For every question Liam answered wrongly, Liam will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Liam only scored 24 marks, therefore Liam totally lost
\begin{array}{rcl}
24-24=0.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
0\div3=0.
\end{array}
The number of correct answers is
\begin{array}{rcl}
12-0=12.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 12, we have,
\begin{array}{rcl}
C+W=12.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=24.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=36.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&36\div3\\
&=&12.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&12-12\\
&=&0.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Liam answered all the 12 questions correctly, and each correct answer has 2 marks, then Liam should score 24 marks,
\begin{array}{rcl}
12\times2=24.
\end{array}
For every question Liam answered wrongly, Liam will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Liam only scored 24 marks, therefore Liam totally lost
\begin{array}{rcl}
24-24=0.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
0\div3=0.
\end{array}
The number of correct answers is
\begin{array}{rcl}
12-0=12.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 12, we have,
\begin{array}{rcl}
C+W=12.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=24.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=36.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&36\div3\\
&=&12.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&12-12\\
&=&0.\tag{6}
\end{array}

Noah attended a Australian Maths Trust (AMT). Noah answered all 37 questions. For each correct answer, Noah will get 4 marks. However, for each wrong answer, Noah will be deducted by 1 mark(s). If Noah scored 68 marks in total, how many questions did Noah answer wrongly?

20

23

22

16

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Noah answered all the 37 questions correctly, and each correct answer has 4 marks, then Noah should score 148 marks,
\begin{array}{rcl}
37\times4=148.
\end{array}
For every question Noah answered wrongly, Noah will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Noah only scored 68 marks, therefore Noah totally lost
\begin{array}{rcl}
148-68=80.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
80\div5=16.
\end{array}
The number of correct answers is
\begin{array}{rcl}
37-16=21.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 37, we have,
\begin{array}{rcl}
C+W=37.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=68.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=105.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&105\div5\\
&=&21.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&37-21\\
&=&16.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Noah answered all the 37 questions correctly, and each correct answer has 4 marks, then Noah should score 148 marks,
\begin{array}{rcl}
37\times4=148.
\end{array}
For every question Noah answered wrongly, Noah will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Noah only scored 68 marks, therefore Noah totally lost
\begin{array}{rcl}
148-68=80.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
80\div5=16.
\end{array}
The number of correct answers is
\begin{array}{rcl}
37-16=21.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 37, we have,
\begin{array}{rcl}
C+W=37.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=68.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=105.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&105\div5\\
&=&21.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&37-21\\
&=&16.\tag{6}
\end{array}

Emma attended a English Spelling Bee Competition. Emma answered all 45 questions. For each correct answer, Emma will get 4 marks. However, for each wrong answer, Emma will be deducted by 1 mark(s). If Emma scored 80 marks in total, how many questions did Emma answer correctly?

21

26

29

25

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Emma answered all the 45 questions correctly, and each correct answer has 4 marks, then Emma should score 180 marks,
\begin{array}{rcl}
45\times4=180.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Emma only scored 80 marks, therefore Emma totally lost
\begin{array}{rcl}
180-80=100.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
100\div5=20.
\end{array}
The number of correct answers is
\begin{array}{rcl}
45-20=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 45, we have,
\begin{array}{rcl}
C+W=45.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=80.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=125.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&125\div5\\
&=&25.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&45-25\\
&=&20.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Emma answered all the 45 questions correctly, and each correct answer has 4 marks, then Emma should score 180 marks,
\begin{array}{rcl}
45\times4=180.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Emma only scored 80 marks, therefore Emma totally lost
\begin{array}{rcl}
180-80=100.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
100\div5=20.
\end{array}
The number of correct answers is
\begin{array}{rcl}
45-20=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 45, we have,
\begin{array}{rcl}
C+W=45.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=80.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=125.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&125\div5\\
&=&25.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&45-25\\
&=&20.\tag{6}
\end{array}

James attended a American Maths Olympiad (AMO). James answered all 40 questions. For each correct answer, James will get 3 marks. However, for each wrong answer, James will be deducted by 1 mark(s). If James scored 60 marks in total, how many questions did James answer wrongly?

15

27

25

11

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume James answered all the 40 questions correctly, and each correct answer has 3 marks, then James should score 120 marks,
\begin{array}{rcl}
40\times3=120.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since James only scored 60 marks, therefore James totally lost
\begin{array}{rcl}
120-60=60.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
60\div4=15.
\end{array}
The number of correct answers is
\begin{array}{rcl}
40-15=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 40, we have,
\begin{array}{rcl}
C+W=40.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=60.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=100.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&100\div4\\
&=&25.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&40-25\\
&=&15.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume James answered all the 40 questions correctly, and each correct answer has 3 marks, then James should score 120 marks,
\begin{array}{rcl}
40\times3=120.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since James only scored 60 marks, therefore James totally lost
\begin{array}{rcl}
120-60=60.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
60\div4=15.
\end{array}
The number of correct answers is
\begin{array}{rcl}
40-15=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 40, we have,
\begin{array}{rcl}
C+W=40.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=60.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=100.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&100\div4\\
&=&25.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&40-25\\
&=&15.\tag{6}
\end{array}

William attended a Maths Competition. William answered all 56 questions. For each correct answer, William will get 3 marks. However, for each wrong answer, William will be deducted by 1 mark(s). If William scored 48 marks in total, how many questions did William answer wrongly?

24

30

27

26

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume William answered all the 56 questions correctly, and each correct answer has 3 marks, then William should score 168 marks,
\begin{array}{rcl}
56\times3=168.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since William only scored 48 marks, therefore William totally lost
\begin{array}{rcl}
168-48=120.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
120\div4=30.
\end{array}
The number of correct answers is
\begin{array}{rcl}
56-30=26.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 56, we have,
\begin{array}{rcl}
C+W=56.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=48.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=104.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&104\div4\\
&=&26.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&56-26\\
&=&30.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume William answered all the 56 questions correctly, and each correct answer has 3 marks, then William should score 168 marks,
\begin{array}{rcl}
56\times3=168.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since William only scored 48 marks, therefore William totally lost
\begin{array}{rcl}
168-48=120.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
120\div4=30.
\end{array}
The number of correct answers is
\begin{array}{rcl}
56-30=26.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 56, we have,
\begin{array}{rcl}
C+W=56.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=48.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=104.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&104\div4\\
&=&26.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&56-26\\
&=&30.\tag{6}
\end{array}

Liam attended a English Spelling Bee Competition. Liam answered all 22 questions. For each correct answer, Liam will get 2 marks. However, for each wrong answer, Liam will be deducted by 1 mark(s). If Liam scored 38 marks in total, how many questions did Liam answer correctly?

24

20

21

23

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Liam answered all the 22 questions correctly, and each correct answer has 2 marks, then Liam should score 44 marks,
\begin{array}{rcl}
22\times2=44.
\end{array}
For every question Liam answered wrongly, Liam will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Liam only scored 38 marks, therefore Liam totally lost
\begin{array}{rcl}
44-38=6.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
6\div3=2.
\end{array}
The number of correct answers is
\begin{array}{rcl}
22-2=20.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 22, we have,
\begin{array}{rcl}
C+W=22.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=38.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=60.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&60\div3\\
&=&20.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&22-20\\
&=&2.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Liam answered all the 22 questions correctly, and each correct answer has 2 marks, then Liam should score 44 marks,
\begin{array}{rcl}
22\times2=44.
\end{array}
For every question Liam answered wrongly, Liam will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Liam only scored 38 marks, therefore Liam totally lost
\begin{array}{rcl}
44-38=6.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
6\div3=2.
\end{array}
The number of correct answers is
\begin{array}{rcl}
22-2=20.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 22, we have,
\begin{array}{rcl}
C+W=22.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=38.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=60.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&60\div3\\
&=&20.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&22-20\\
&=&2.\tag{6}
\end{array}

Ava attended a Australian Maths Trust (AMT). Ava answered all 57 questions. For each correct answer, Ava will get 4 marks. However, for each wrong answer, Ava will be deducted by 2 mark(s). If Ava scored 60 marks in total, how many questions did Ava answer wrongly?

30

36

28

34

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Ava answered all the 57 questions correctly, and each correct answer has 4 marks, then Ava should score 228 marks,
\begin{array}{rcl}
57\times4=228.
\end{array}
For every question Ava answered wrongly, Ava will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Ava only scored 60 marks, therefore Ava totally lost
\begin{array}{rcl}
228-60=168.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
168\div6=28.
\end{array}
The number of correct answers is
\begin{array}{rcl}
57-28=29.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 57, we have,
\begin{array}{rcl}
C+W=57.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=60.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=114.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=174.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&174\div6\\
&=&29.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&57-29\\
&=&28.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Ava answered all the 57 questions correctly, and each correct answer has 4 marks, then Ava should score 228 marks,
\begin{array}{rcl}
57\times4=228.
\end{array}
For every question Ava answered wrongly, Ava will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Ava only scored 60 marks, therefore Ava totally lost
\begin{array}{rcl}
228-60=168.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
168\div6=28.
\end{array}
The number of correct answers is
\begin{array}{rcl}
57-28=29.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 57, we have,
\begin{array}{rcl}
C+W=57.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=60.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=114.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=174.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&174\div6\\
&=&29.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&57-29\\
&=&28.\tag{6}
\end{array}

Larry Page attended a Australian Maths Trust (AMT). Larry Page answered all 72 questions. For each correct answer, Larry Page will get 8 marks. However, for each wrong answer, Larry Page will be deducted by 2 mark(s). If Larry Page scored 96 marks in total, how many questions did Larry Page answer correctly?

24

21

23

22

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Larry Page answered all the 72 questions correctly, and each correct answer has 8 marks, then Larry Page should score 576 marks,
\begin{array}{rcl}
72\times8=576.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Larry Page only scored 96 marks, therefore Larry Page totally lost
\begin{array}{rcl}
576-96=480.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
480\div10=48.
\end{array}
The number of correct answers is
\begin{array}{rcl}
72-48=24.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 72, we have,
\begin{array}{rcl}
C+W=72.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=96.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=144.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=240.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&240\div10\\
&=&24.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&72-24\\
&=&48.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Larry Page answered all the 72 questions correctly, and each correct answer has 8 marks, then Larry Page should score 576 marks,
\begin{array}{rcl}
72\times8=576.
\end{array}
For every question Larry Page answered wrongly, Larry Page will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Larry Page only scored 96 marks, therefore Larry Page totally lost
\begin{array}{rcl}
576-96=480.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
480\div10=48.
\end{array}
The number of correct answers is
\begin{array}{rcl}
72-48=24.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 72, we have,
\begin{array}{rcl}
C+W=72.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=96.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=144.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=240.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&240\div10\\
&=&24.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&72-24\\
&=&48.\tag{6}
\end{array}

Isabella attended a Singapore Maths Olympaid (SMO). Isabella answered all 69 questions. For each correct answer, Isabella will get 8 marks. However, for each wrong answer, Isabella will be deducted by 2 mark(s). If Isabella scored 152 marks in total, how many questions did Isabella answer wrongly?

46

36

41

40

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Isabella answered all the 69 questions correctly, and each correct answer has 8 marks, then Isabella should score 552 marks,
\begin{array}{rcl}
69\times8=552.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Isabella only scored 152 marks, therefore Isabella totally lost
\begin{array}{rcl}
552-152=400.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
400\div10=40.
\end{array}
The number of correct answers is
\begin{array}{rcl}
69-40=29.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 69, we have,
\begin{array}{rcl}
C+W=69.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=152.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=138.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=290.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&290\div10\\
&=&29.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&69-29\\
&=&40.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Isabella answered all the 69 questions correctly, and each correct answer has 8 marks, then Isabella should score 552 marks,
\begin{array}{rcl}
69\times8=552.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Isabella only scored 152 marks, therefore Isabella totally lost
\begin{array}{rcl}
552-152=400.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
400\div10=40.
\end{array}
The number of correct answers is
\begin{array}{rcl}
69-40=29.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 69, we have,
\begin{array}{rcl}
C+W=69.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=152.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=138.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=290.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&290\div10\\
&=&29.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&69-29\\
&=&40.\tag{6}
\end{array}

Benjamin attended a Maths Competition. Benjamin answered all 72 questions. For each correct answer, Benjamin will get 8 marks. However, for each wrong answer, Benjamin will be deducted by 2 mark(s). If Benjamin scored 96 marks in total, how many questions did Benjamin answer correctly?

26

27

21

24

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Benjamin answered all the 72 questions correctly, and each correct answer has 8 marks, then Benjamin should score 576 marks,
\begin{array}{rcl}
72\times8=576.
\end{array}
For every question Benjamin answered wrongly, Benjamin will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Benjamin only scored 96 marks, therefore Benjamin totally lost
\begin{array}{rcl}
576-96=480.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
480\div10=48.
\end{array}
The number of correct answers is
\begin{array}{rcl}
72-48=24.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 72, we have,
\begin{array}{rcl}
C+W=72.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=96.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=144.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=240.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&240\div10\\
&=&24.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&72-24\\
&=&48.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Benjamin answered all the 72 questions correctly, and each correct answer has 8 marks, then Benjamin should score 576 marks,
\begin{array}{rcl}
72\times8=576.
\end{array}
For every question Benjamin answered wrongly, Benjamin will lose,
\begin{array}{rcl}
8+2=10.
\end{array}
marks.

Since Benjamin only scored 96 marks, therefore Benjamin totally lost
\begin{array}{rcl}
576-96=480.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
480\div10=48.
\end{array}
The number of correct answers is
\begin{array}{rcl}
72-48=24.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 72, we have,
\begin{array}{rcl}
C+W=72.\tag{1}
\end{array}
Since for every correct answer gives 8 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
8C-2W=96.\tag{2}
\end{array}
Multiplying both sides of (1) by 8 we have,
\begin{array}{rcl}
2C+2W=144.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
10C=240.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&240\div10\\
&=&24.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&72-24\\
&=&48.\tag{6}
\end{array}

Isabella attended a Chinese Multiple Choices Test. Isabella answered all 23 questions. For each correct answer, Isabella will get 3 marks. However, for each wrong answer, Isabella will be deducted by 1 mark(s). If Isabella scored 33 marks in total, how many questions did Isabella answer correctly?

18

14

19

15

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Isabella answered all the 23 questions correctly, and each correct answer has 3 marks, then Isabella should score 69 marks,
\begin{array}{rcl}
23\times3=69.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since Isabella only scored 33 marks, therefore Isabella totally lost
\begin{array}{rcl}
69-33=36.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
36\div4=9.
\end{array}
The number of correct answers is
\begin{array}{rcl}
23-9=14.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 23, we have,
\begin{array}{rcl}
C+W=23.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=33.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=56.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&56\div4\\
&=&14.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&23-14\\
&=&9.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Isabella answered all the 23 questions correctly, and each correct answer has 3 marks, then Isabella should score 69 marks,
\begin{array}{rcl}
23\times3=69.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
3+1=4.
\end{array}
marks.

Since Isabella only scored 33 marks, therefore Isabella totally lost
\begin{array}{rcl}
69-33=36.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
36\div4=9.
\end{array}
The number of correct answers is
\begin{array}{rcl}
23-9=14.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 23, we have,
\begin{array}{rcl}
C+W=23.\tag{1}
\end{array}
Since for every correct answer gives 3 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
3C-1W=33.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
4C=56.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&56\div4\\
&=&14.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&23-14\\
&=&9.\tag{6}
\end{array}

Emma attended a South-East Asia Maths Olympaid (SEAMO). Emma answered all 48 questions. For each correct answer, Emma will get 10 marks. However, for each wrong answer, Emma will be deducted by 2 mark(s). If Emma scored 120 marks in total, how many questions did Emma answer wrongly?

26

29

31

30

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Emma answered all the 48 questions correctly, and each correct answer has 10 marks, then Emma should score 480 marks,
\begin{array}{rcl}
48\times10=480.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Emma only scored 120 marks, therefore Emma totally lost
\begin{array}{rcl}
480-120=360.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
360\div12=30.
\end{array}
The number of correct answers is
\begin{array}{rcl}
48-30=18.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 48, we have,
\begin{array}{rcl}
C+W=48.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=120.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=96.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=216.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&216\div12\\
&=&18.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&48-18\\
&=&30.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Emma answered all the 48 questions correctly, and each correct answer has 10 marks, then Emma should score 480 marks,
\begin{array}{rcl}
48\times10=480.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Emma only scored 120 marks, therefore Emma totally lost
\begin{array}{rcl}
480-120=360.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
360\div12=30.
\end{array}
The number of correct answers is
\begin{array}{rcl}
48-30=18.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 48, we have,
\begin{array}{rcl}
C+W=48.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=120.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=96.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=216.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&216\div12\\
&=&18.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&48-18\\
&=&30.\tag{6}
\end{array}

Olivia attended a American Maths Olympiad (AMO). Olivia answered all 43 questions. For each correct answer, Olivia will get 2 marks. However, for each wrong answer, Olivia will be deducted by 1 mark(s). If Olivia scored 32 marks in total, how many questions did Olivia answer correctly?

27

25

20

24

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Olivia answered all the 43 questions correctly, and each correct answer has 2 marks, then Olivia should score 86 marks,
\begin{array}{rcl}
43\times2=86.
\end{array}
For every question Olivia answered wrongly, Olivia will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Olivia only scored 32 marks, therefore Olivia totally lost
\begin{array}{rcl}
86-32=54.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
54\div3=18.
\end{array}
The number of correct answers is
\begin{array}{rcl}
43-18=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 43, we have,
\begin{array}{rcl}
C+W=43.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=32.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=75.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&75\div3\\
&=&25.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&43-25\\
&=&18.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Olivia answered all the 43 questions correctly, and each correct answer has 2 marks, then Olivia should score 86 marks,
\begin{array}{rcl}
43\times2=86.
\end{array}
For every question Olivia answered wrongly, Olivia will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since Olivia only scored 32 marks, therefore Olivia totally lost
\begin{array}{rcl}
86-32=54.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
54\div3=18.
\end{array}
The number of correct answers is
\begin{array}{rcl}
43-18=25.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 43, we have,
\begin{array}{rcl}
C+W=43.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=32.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=75.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&75\div3\\
&=&25.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&43-25\\
&=&18.\tag{6}
\end{array}

Sophia attended a Chinese Multiple Choices Test. Sophia answered all 34 questions. For each correct answer, Sophia will get 4 marks. However, for each wrong answer, Sophia will be deducted by 2 mark(s). If Sophia scored 40 marks in total, how many questions did Sophia answer wrongly?

18

16

17

20

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Sophia answered all the 34 questions correctly, and each correct answer has 4 marks, then Sophia should score 136 marks,
\begin{array}{rcl}
34\times4=136.
\end{array}
For every question Sophia answered wrongly, Sophia will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Sophia only scored 40 marks, therefore Sophia totally lost
\begin{array}{rcl}
136-40=96.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
96\div6=16.
\end{array}
The number of correct answers is
\begin{array}{rcl}
34-16=18.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 34, we have,
\begin{array}{rcl}
C+W=34.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=40.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=68.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=108.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&108\div6\\
&=&18.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&34-18\\
&=&16.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Sophia answered all the 34 questions correctly, and each correct answer has 4 marks, then Sophia should score 136 marks,
\begin{array}{rcl}
34\times4=136.
\end{array}
For every question Sophia answered wrongly, Sophia will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since Sophia only scored 40 marks, therefore Sophia totally lost
\begin{array}{rcl}
136-40=96.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
96\div6=16.
\end{array}
The number of correct answers is
\begin{array}{rcl}
34-16=18.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 34, we have,
\begin{array}{rcl}
C+W=34.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=40.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=68.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=108.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&108\div6\\
&=&18.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&34-18\\
&=&16.\tag{6}
\end{array}

James attended a Singapore Maths Olympaid (SMO). James answered all 98 questions. For each correct answer, James will get 6 marks. However, for each wrong answer, James will be deducted by 2 mark(s). If James scored 108 marks in total, how many questions did James answer wrongly?

38

40

66

60

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume James answered all the 98 questions correctly, and each correct answer has 6 marks, then James should score 588 marks,
\begin{array}{rcl}
98\times6=588.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since James only scored 108 marks, therefore James totally lost
\begin{array}{rcl}
588-108=480.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
480\div8=60.
\end{array}
The number of correct answers is
\begin{array}{rcl}
98-60=38.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 98, we have,
\begin{array}{rcl}
C+W=98.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=108.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=196.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=304.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&304\div8\\
&=&38.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&98-38\\
&=&60.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume James answered all the 98 questions correctly, and each correct answer has 6 marks, then James should score 588 marks,
\begin{array}{rcl}
98\times6=588.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since James only scored 108 marks, therefore James totally lost
\begin{array}{rcl}
588-108=480.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
480\div8=60.
\end{array}
The number of correct answers is
\begin{array}{rcl}
98-60=38.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 98, we have,
\begin{array}{rcl}
C+W=98.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=108.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=196.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=304.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&304\div8\\
&=&38.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&98-38\\
&=&60.\tag{6}
\end{array}

Isabella attended a English Spelling Bee Competition. Isabella answered all 21 questions. For each correct answer, Isabella will get 6 marks. However, for each wrong answer, Isabella will be deducted by 2 mark(s). If Isabella scored 78 marks in total, how many questions did Isabella answer wrongly?

14

6

8

13

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Isabella answered all the 21 questions correctly, and each correct answer has 6 marks, then Isabella should score 126 marks,
\begin{array}{rcl}
21\times6=126.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since Isabella only scored 78 marks, therefore Isabella totally lost
\begin{array}{rcl}
126-78=48.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
48\div8=6.
\end{array}
The number of correct answers is
\begin{array}{rcl}
21-6=15.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 21, we have,
\begin{array}{rcl}
C+W=21.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=78.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=42.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=120.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&120\div8\\
&=&15.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&21-15\\
&=&6.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Isabella answered all the 21 questions correctly, and each correct answer has 6 marks, then Isabella should score 126 marks,
\begin{array}{rcl}
21\times6=126.
\end{array}
For every question Isabella answered wrongly, Isabella will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since Isabella only scored 78 marks, therefore Isabella totally lost
\begin{array}{rcl}
126-78=48.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
48\div8=6.
\end{array}
The number of correct answers is
\begin{array}{rcl}
21-6=15.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 21, we have,
\begin{array}{rcl}
C+W=21.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=78.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=42.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=120.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&120\div8\\
&=&15.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&21-15\\
&=&6.\tag{6}
\end{array}

Emma attended a Maths Competition. Emma answered all 50 questions. For each correct answer, Emma will get 5 marks. However, for each wrong answer, Emma will be deducted by 1 mark(s). If Emma scored 70 marks in total, how many questions did Emma answer correctly?

16

26

18

20

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Emma answered all the 50 questions correctly, and each correct answer has 5 marks, then Emma should score 250 marks,
\begin{array}{rcl}
50\times5=250.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since Emma only scored 70 marks, therefore Emma totally lost
\begin{array}{rcl}
250-70=180.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
180\div6=30.
\end{array}
The number of correct answers is
\begin{array}{rcl}
50-30=20.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 50, we have,
\begin{array}{rcl}
C+W=50.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=70.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=120.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&120\div6\\
&=&20.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&50-20\\
&=&30.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Emma answered all the 50 questions correctly, and each correct answer has 5 marks, then Emma should score 250 marks,
\begin{array}{rcl}
50\times5=250.
\end{array}
For every question Emma answered wrongly, Emma will lose,
\begin{array}{rcl}
5+1=6.
\end{array}
marks.

Since Emma only scored 70 marks, therefore Emma totally lost
\begin{array}{rcl}
250-70=180.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
180\div6=30.
\end{array}
The number of correct answers is
\begin{array}{rcl}
50-30=20.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 50, we have,
\begin{array}{rcl}
C+W=50.\tag{1}
\end{array}
Since for every correct answer gives 5 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
5C-1W=70.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
6C=120.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&120\div6\\
&=&20.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&50-20\\
&=&30.\tag{6}
\end{array}

James attended a Australian Maths Trust (AMT). James answered all 31 questions. For each correct answer, James will get 2 marks. However, for each wrong answer, James will be deducted by 1 mark(s). If James scored 26 marks in total, how many questions did James answer correctly?

22

19

14

15

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume James answered all the 31 questions correctly, and each correct answer has 2 marks, then James should score 62 marks,
\begin{array}{rcl}
31\times2=62.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since James only scored 26 marks, therefore James totally lost
\begin{array}{rcl}
62-26=36.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
36\div3=12.
\end{array}
The number of correct answers is
\begin{array}{rcl}
31-12=19.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 31, we have,
\begin{array}{rcl}
C+W=31.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=26.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=57.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&57\div3\\
&=&19.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&31-19\\
&=&12.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume James answered all the 31 questions correctly, and each correct answer has 2 marks, then James should score 62 marks,
\begin{array}{rcl}
31\times2=62.
\end{array}
For every question James answered wrongly, James will lose,
\begin{array}{rcl}
2+1=3.
\end{array}
marks.

Since James only scored 26 marks, therefore James totally lost
\begin{array}{rcl}
62-26=36.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
36\div3=12.
\end{array}
The number of correct answers is
\begin{array}{rcl}
31-12=19.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 31, we have,
\begin{array}{rcl}
C+W=31.\tag{1}
\end{array}
Since for every correct answer gives 2 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
2C-1W=26.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
3C=57.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&57\div3\\
&=&19.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&31-19\\
&=&12.\tag{6}
\end{array}

Jacob attended a Maths Competition. Jacob answered all 43 questions. For each correct answer, Jacob will get 6 marks. However, for each wrong answer, Jacob will be deducted by 2 mark(s). If Jacob scored 66 marks in total, how many questions did Jacob answer wrongly?

24

21

26

32

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Jacob answered all the 43 questions correctly, and each correct answer has 6 marks, then Jacob should score 258 marks,
\begin{array}{rcl}
43\times6=258.
\end{array}
For every question Jacob answered wrongly, Jacob will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since Jacob only scored 66 marks, therefore Jacob totally lost
\begin{array}{rcl}
258-66=192.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
192\div8=24.
\end{array}
The number of correct answers is
\begin{array}{rcl}
43-24=19.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 43, we have,
\begin{array}{rcl}
C+W=43.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=66.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=86.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=152.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&152\div8\\
&=&19.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&43-19\\
&=&24.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Jacob answered all the 43 questions correctly, and each correct answer has 6 marks, then Jacob should score 258 marks,
\begin{array}{rcl}
43\times6=258.
\end{array}
For every question Jacob answered wrongly, Jacob will lose,
\begin{array}{rcl}
6+2=8.
\end{array}
marks.

Since Jacob only scored 66 marks, therefore Jacob totally lost
\begin{array}{rcl}
258-66=192.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
192\div8=24.
\end{array}
The number of correct answers is
\begin{array}{rcl}
43-24=19.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 43, we have,
\begin{array}{rcl}
C+W=43.\tag{1}
\end{array}
Since for every correct answer gives 6 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
6C-2W=66.\tag{2}
\end{array}
Multiplying both sides of (1) by 6 we have,
\begin{array}{rcl}
2C+2W=86.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
8C=152.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&152\div8\\
&=&19.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&43-19\\
&=&24.\tag{6}
\end{array}

Mason attended a Australian Maths Trust (AMT). Mason answered all 137 questions. For each correct answer, Mason will get 10 marks. However, for each wrong answer, Mason will be deducted by 2 mark(s). If Mason scored 170 marks in total, how many questions did Mason answer wrongly?

100

95

96

39

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Mason answered all the 137 questions correctly, and each correct answer has 10 marks, then Mason should score 1370 marks,
\begin{array}{rcl}
137\times10=1370.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Mason only scored 170 marks, therefore Mason totally lost
\begin{array}{rcl}
1370-170=1200.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
1200\div12=100.
\end{array}
The number of correct answers is
\begin{array}{rcl}
137-100=37.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 137, we have,
\begin{array}{rcl}
C+W=137.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=170.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=274.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=444.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&444\div12\\
&=&37.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&137-37\\
&=&100.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Mason answered all the 137 questions correctly, and each correct answer has 10 marks, then Mason should score 1370 marks,
\begin{array}{rcl}
137\times10=1370.
\end{array}
For every question Mason answered wrongly, Mason will lose,
\begin{array}{rcl}
10+2=12.
\end{array}
marks.

Since Mason only scored 170 marks, therefore Mason totally lost
\begin{array}{rcl}
1370-170=1200.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
1200\div12=100.
\end{array}
The number of correct answers is
\begin{array}{rcl}
137-100=37.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 137, we have,
\begin{array}{rcl}
C+W=137.\tag{1}
\end{array}
Since for every correct answer gives 10 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
10C-2W=170.\tag{2}
\end{array}
Multiplying both sides of (1) by 10 we have,
\begin{array}{rcl}
2C+2W=274.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
12C=444.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&444\div12\\
&=&37.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&137-37\\
&=&100.\tag{6}
\end{array}

William attended a Australian Maths Trust (AMT). William answered all 48 questions. For each correct answer, William will get 4 marks. However, for each wrong answer, William will be deducted by 2 mark(s). If William scored 72 marks in total, how many questions did William answer wrongly?

30

26

27

20

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume William answered all the 48 questions correctly, and each correct answer has 4 marks, then William should score 192 marks,
\begin{array}{rcl}
48\times4=192.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since William only scored 72 marks, therefore William totally lost
\begin{array}{rcl}
192-72=120.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
120\div6=20.
\end{array}
The number of correct answers is
\begin{array}{rcl}
48-20=28.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 48, we have,
\begin{array}{rcl}
C+W=48.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=72.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=96.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=168.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&168\div6\\
&=&28.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&48-28\\
&=&20.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume William answered all the 48 questions correctly, and each correct answer has 4 marks, then William should score 192 marks,
\begin{array}{rcl}
48\times4=192.
\end{array}
For every question William answered wrongly, William will lose,
\begin{array}{rcl}
4+2=6.
\end{array}
marks.

Since William only scored 72 marks, therefore William totally lost
\begin{array}{rcl}
192-72=120.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
120\div6=20.
\end{array}
The number of correct answers is
\begin{array}{rcl}
48-20=28.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 48, we have,
\begin{array}{rcl}
C+W=48.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 2 mark(s), the total score is,
\begin{array}{rcl}
4C-2W=72.\tag{2}
\end{array}
Multiplying both sides of (1) by 4 we have,
\begin{array}{rcl}
2C+2W=96.\tag{3}
\end{array}
We can eliminate $W$ by summing up the left side of (2) and (3), and also summing up the right side of (2) and (3),
\begin{array}{rcl}
6C=168.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&168\div6\\
&=&28.\tag{5}
\end{array}
From (5) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&48-28\\
&=&20.\tag{6}
\end{array}

Liam attended a South-East Asia Maths Olympaid (SEAMO). Liam answered all 11 questions. For each correct answer, Liam will get 4 marks. However, for each wrong answer, Liam will be deducted by 1 mark(s). If Liam scored 44 marks in total, how many questions did Liam answer correctly?

19

14

17

11

Sorry. Please check the correct answer below.

__Method 1: Method of Assumption__

Assume Liam answered all the 11 questions correctly, and each correct answer has 4 marks, then Liam should score 44 marks,
\begin{array}{rcl}
11\times4=44.
\end{array}
For every question Liam answered wrongly, Liam will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Liam only scored 44 marks, therefore Liam totally lost
\begin{array}{rcl}
44-44=0.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
0\div5=0.
\end{array}
The number of correct answers is
\begin{array}{rcl}
11-0=11.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 11, we have,
\begin{array}{rcl}
C+W=11.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=44.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=55.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&55\div5\\
&=&11.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&11-11\\
&=&0.\tag{6}
\end{array}

You are Right

__Method 1: Method of Assumption__

Assume Liam answered all the 11 questions correctly, and each correct answer has 4 marks, then Liam should score 44 marks,
\begin{array}{rcl}
11\times4=44.
\end{array}
For every question Liam answered wrongly, Liam will lose,
\begin{array}{rcl}
4+1=5.
\end{array}
marks.

Since Liam only scored 44 marks, therefore Liam totally lost
\begin{array}{rcl}
44-44=0.
\end{array}
marks due to the questions answered wrongly.

Therefore the number of wrong answers is
\begin{array}{rcl}
0\div5=0.
\end{array}
The number of correct answers is
\begin{array}{rcl}
11-0=11.
\end{array}
__Method 2: Simple Algebra__

Let the number of correct answers be $C$, and the number of wrong answer be $W$.

Since the total number of questions is 11, we have,
\begin{array}{rcl}
C+W=11.\tag{1}
\end{array}
Since for every correct answer gives 4 marks, and every wrong aswer deducts 1 mark(s), the total score is,
\begin{array}{rcl}
4C-1W=44.\tag{2}
\end{array}
We can eliminate $W$ by summing up the left side of (1) and (2), and also summing up the right side of (1) and (2),
\begin{array}{rcl}
5C=55.\tag{4}
\end{array}
Therefore the number of correct answer is
\begin{array}{rcl}
C&=&55\div5\\
&=&11.\tag{5}
\end{array}
From (4) and (1) we have the number of wrong answer
\begin{array}{rcl}
W&=&11-11\\
&=&0.\tag{6}
\end{array}

Sophia attended a Maths Competition. Sophia answered all 13 questions. For each correct answer, Sophia will get 4 marks. However, for each wrong answer, Sophia will be deducted by 1 mark(s). If Sophia scored 52 marks in total, how many questions did Sophia answer wrongly?

13

6

0

11