$Logo$

Numbers
Measurement
Data Analysis
Geometry
Speed
- Simple Speed Question: Determine the speed distance and time
Others
P5 Maths
P4 Maths

Home
Geometry
Trapezoid

Tap to switch levels

Numbers

What does the number stand for?

Nearest number

Which digit is in the place?

Round off to the nearest number

Number divide

Find the fraction nearest to 1

Sort fraction numbers

Find the largest or smallest fraction

Fraction to decimal

Convert decimal to a mixed fraction.

Fraction - Addition

Fraction - Substraction

Fraction - Multiply

Fraction - Divide

List all the common factors of two integers

Chicken and Rabbit problem

Assumption Method

Measurement

Measurement Questions Length

Measurement Questions Mass or Weight

Measurement Questions Time

Measurement Questions Volume

Geometry

Angles

Triangles

Squares and Rectangles

Circles

Nets

Area of Composites

Rhombus

Trapezoid

Speed

Simple Speed Question: Determine the speed distance and time

Others

Patterns

Mental Sum Practice 1

Mental Sum Practice 2

Mental Sum Practice 3

P5 Maths

P5 Fractions I

Whole Numbers

Nets and Patterns

Method of Assumption

Excess and Shortage

Revision I

Fractions II

Working Backward

P4 Maths

Factors and Multiples I

Whole Numbers

Fractions I

Method of Assumption

Term Revision I

Patterns P4

Interval Problems

Question 1 of 25

In the figure below, not drawn to scale, WXYZ is a trapezium. AY, GW and YC are straight line. Find $\angle$YWX

$Question Image of In the figure below, not drawn to scale, WXYZ is a trapezium. AY, GW and YC are straight line. Find $\angle$YWX.$

68$^\circ$

70$^\circ$

72$^\circ$

74$^\circ$

None of the above

Sorry. Please check the correct answer below.

$180^\circ - 78^\circ = 102^\circ$
$180^\circ - 102^\circ – 42^\circ= 36^\circ$
$(180^\circ - 36^\circ) ÷ 2= 72^\circ$

View Correct Answer

72$^\circ$

You are Right

$180^\circ - 78^\circ = 102^\circ$
$180^\circ - 102^\circ – 42^\circ= 36^\circ$
$(180^\circ - 36^\circ) ÷ 2= 72^\circ$

The line PQ and QR are part of an incomplete trapezium PQRS. Complete drawing the trapezium such that $\angle$QRS = 120$^\circ$. Measure the line PS.

$Question Image of The line PQ and QR are part of an incomplete trapezium PQRS. Complete drawing the trapezium such that $\angle$QRS = 120$^\circ$. Measure the line PS. .$

6.2cm

6.4cm

9.2cm

9.4cm

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

9.4cm

You are Right

In the figure below, ABCD is a trapezium and PQCR is a square. The size of $\angle$DCR is $\frac{5}{4}$ of $\angle$DCQ. Find $\angle$DSQ?

$Question Image$

120$^\circ$

140$^\circ$

160$^\circ$

180$^\circ$

None of the above

Sorry. Please check the correct answer below.

$180 – 110 = 70$
$5 + 4 = 9$
$90 \div 9 = 10$
$10 \times 5 = 50$
$90 – 50 = 40$
$180 – 70 – 40 = 70$
$180 \times 2 = 360$
$\angle$DSQ = $360 – 70 – 79 – 40 = 160$

View Correct Answer

160$^\circ$

You are Right

$180 – 110 = 70$
$5 + 4 = 9$
$90 \div 9 = 10$
$10 \times 5 = 50$
$90 – 50 = 40$
$180 – 70 – 40 = 70$
$180 \times 2 = 360$
$\angle$DSQ = $360 – 70 – 79 – 40 = 160$

The figure shown below, a trapezium ABCD was folded as shown. AB is parallel to CD. AE is parallel to BF. $\angle$AEF = 65$^\circ$. Find $\angle$FAE.

$Question Image$

20$^\circ$

30$^\circ$

40$^\circ$

50$^\circ$

None of the above

Sorry. Please check the correct answer below.

$\angle$XDA $\rightarrow$ 65$^\circ$
$\angle$CDX $\rightarrow$ 65$^\circ$
$\angle$DXB $\rightarrow$ $180^\circ – 65^\circ = 115^\circ$
$\angle$DAX = $\angle$FAE $\rightarrow$ $150^\circ – 65^\circ = 50^\circ$

View Correct Answer

50$^\circ$

You are Right

The figure below shows a trapezium PQRS. What is the area of the shaded part?

$Question Image$

43.5

45.5

47.5

49.5

None of the above

Sorry. Please check the correct answer below.

Area of Shaded Part = $\frac{1}{2} \times 9 \times 11 = 49.5$

View Correct Answer

49.5

You are Right

Area of Shaded Part = $\frac{1}{2} \times 9 \times 11 = 49.5$

The figure below shows a trapezium. Which one of the following options is correct?

$Question Image$

$\angle$a = $\angle$c

$\angle$a = $\angle$b

$\angle$a + $\angle$b = $\angle$c + $\angle$d

$\angle$a +$\angle$d = $\angle$c + $\angle$b

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

$\angle$a +$\angle$d = $\angle$c + $\angle$b

You are Right

ABCD is a trapezium. AB is parallel to DC. Which one of the following statements is true?

$Question Image$

$\angle$DAB = $\angle$ADC

$\angle$DAB + $\angle$ADC = 180$^\circ$

$\angle$DAB + $\angle$ABC = 180$^\circ$

$\angle$DAB = $\angle$DCB

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

$\angle$DAB + $\angle$ADC = 180$^\circ$

You are Right

The figure below shows a trapezium ABCD. AD is parallel to BE and BE = BC. $\angle$BEC = 70$^\circ$
(a) Find $\angle$ADC
(b) Find $\angle$ABC.

$Question Image$

(a) 50$^\circ$
(b) 100$^\circ$

(a) 60$^\circ$
(b) 105$^\circ$

(a) 70$^\circ$
(b) 110$^\circ$

(a) 80$^\circ$
(b) 115$^\circ$

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

(a) 70$^\circ$
(b) 110$^\circ$

You are Right

In the figure, ABCD is a trapezium where AD is parallel to BC. Find $\angle$BDC.

$Question Image$

30$^\circ$

35$^\circ$

40$^\circ$

45$^\circ$

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

35$^\circ$

You are Right

In the figure, YZ is a straight line while ABCD and PQRS are overlapping trapeziums. Given that $\angle$YAB = 50$^\circ$, $\angle$QDW = 135$^\circ$,$\angle$DQR = 60$^\circ$,
(a) Find $\angle$DXS.
(b) Find $\angle$QRW.

$Question Image$

(a) 50$^\circ$
(b) 75$^\circ$

(a) 60$^\circ$
(b) 80$^\circ$

(a) 70$^\circ$
(b) 85$^\circ$

(a) 80$^\circ$
(b) 90$^\circ$

None of the above

Sorry. Please check the correct answer below.

(a) $180^\circ - 50^\circ - 90^\circ = 40^\circ$
$180^\circ - 40^\circ - 90^\circ = 50^\circ$
(b) $180^\circ - 50^\circ = 130^\circ$
$360^\circ - 130^\circ - 135^\circ = 95^\circ$
$180^\circ - 45^\circ - 60^\circ = 75^\circ$

View Correct Answer

(a) 50$^\circ$
(b) 75$^\circ$

You are Right

In the figure, ABCD is a trapezium and BCD is an isosceles triangle. DB = DC, BAF = 52$^\circ$ and $\angle$AFE = 110$^\circ$. Find $\angle$BDC.

$Question Image$

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

You are Right

The figure below is not drawn to scale. ACDE is a trapezium. Given the AE = AB, $\angle$EAB =78$^\circ $ and $\angle$ACD is 90 $^\circ $ .
(a) Find $\angle$CDE.
(b) Find $\angle$ABE.
(c) Find $\angle$DEB.

$Question Image$

(a) 102$^\circ$
(b) 51$^\circ$
(c) 51$^\circ$

(a) 104$^\circ$
(b) 53$^\circ$
(c) 52$^\circ$

(a) 106$^\circ$
(b) 55$^\circ$
(c) 53$^\circ$

(a) 108$^\circ$
(b) 57$^\circ$
(c) 54$^\circ$

None of the above

Sorry. Please check the correct answer below.

(a) $180^\circ - 99^\circ = 81^\circ$
(b) $180^\circ - 78^\circ = 102^\circ$
$102^\circ ÷ 2 = 51^\circ$
(c) $\angle$DEB = $\angle$AEB = 51$^\circ$

View Correct Answer

(a) 102$^\circ$
(b) 51$^\circ$
(c) 51$^\circ$

You are Right

(a) $180^\circ - 99^\circ = 81^\circ$
(b) $180^\circ - 78^\circ = 102^\circ$
$102^\circ ÷ 2 = 51^\circ$
(c) $\angle$DEB = $\angle$AEB = 51$^\circ$

The figure below is not drawn to scale. ABCD is a trapezium and $\angle$ BDC = $\angle$ ADB. Find $\angle$ CAD.

$Question Image$

120$^\circ$

125$^\circ$

130$^\circ$

135$^\circ$

None of the above

Sorry. Please check the correct answer below.

120$^\circ$ $\rightarrow$ $360 – 280 = 80$
$80 ÷ 2 = 40$
$\angle$ CAD = $180^\circ - 40^\circ - 20^\circ = 120^\circ$

View Correct Answer

120$^\circ$

You are Right

120$^\circ$ $\rightarrow$ $360 – 280 = 80$
$80 ÷ 2 = 40$
$\angle$ CAD = $180^\circ - 40^\circ - 20^\circ = 120^\circ$

ABCD is a trapezium and EBD is an equilateral triangle. Find $\angle$ABE.

$Question Image$

18$^\circ$

20$^\circ$

22$^\circ$

24$^\circ$

None of the above

Sorry. Please check the correct answer below.

$\angle$ABE = $180^\circ - 110^\circ - 50^\circ = 20^\circ$

View Correct Answer

20$^\circ$

You are Right

$\angle$ABE = $180^\circ - 110^\circ - 50^\circ = 20^\circ$

In the figure, ABCD and EFGH are identical rhombuses and BKMN is a trapezium. Which one of the following statements is true?

$Question Image$

HE // GF // KM

AB // DC //KM

AD // BC // NM

HG // EF // NM

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

AD // BC // NM

You are Right

In the figure below, not drawn to scale, ABCD is a trapezium. Find $\angle$ADB.

$Question Image$

10$^\circ$

15$^\circ$

20$^\circ$

25$^\circ$

None of the above

Sorry. Please check the correct answer below.

$180^\circ - 110^\circ = 70^\circ$
$180^\circ - 90^\circ - 45^\circ = 45^\circ$
$70^\circ - 45^\circ = 25^\circ$

View Correct Answer

25$^\circ$

You are Right

$180^\circ - 110^\circ = 70^\circ$
$180^\circ - 90^\circ - 45^\circ = 45^\circ$
$70^\circ - 45^\circ = 25^\circ$

In the figure below, EBCD is a trapezium. ED is parallel to BC. $\angle$FAB = 74$^\circ$ and $\angle$EBC = 113$^\circ$. Find the sum of $\angle$w, $\angle$x, $\angle$y,and $\angle$z.

$Question Image$

213$^\circ$

215$^\circ$

217$^\circ$

219$^\circ$

None of the above

Sorry. Please check the correct answer below.

$180^\circ - 74^\circ = 106^\circ$ $\angle$y + $\angle$z
$180^\circ - 113^\circ = 67^\circ$
$180^\circ – 67^\circ = 113^\circ$ $\angle$x + $\angle$w
$113^\circ + 106^\circ = 219^\circ$

View Correct Answer

219$^\circ$

You are Right

$180^\circ - 74^\circ = 106^\circ$ $\angle$y + $\angle$z
$180^\circ - 113^\circ = 67^\circ$
$180^\circ – 67^\circ = 113^\circ$ $\angle$x + $\angle$w
$113^\circ + 106^\circ = 219^\circ$

The figure is not drawn to scale. ABCD is a trapezium. Find $\angle$ADC.

$Question Image$

79$^\circ$

73$^\circ$

76$^\circ$

80$^\circ$

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

73$^\circ$

You are Right

In the figure below, WXYZ is a trapezium. WZ is parallel to XY. $\angle$XWY = 52$^\circ$,$\angle$WYZ = 66 $^\circ$ and $\angle$WZY = 55$^\circ$. Find $\angle$WXY.

$Question Image$

56$^\circ$

58$^\circ$

60$^\circ$

62$^\circ$

None of the above

Sorry. Please check the correct answer below.

$180^\circ - 70^\circ - 70^\circ = 32^\circ$
$90^\circ - 32^\circ = 58^\circ$

View Correct Answer

58$^\circ$

You are Right

$180^\circ - 70^\circ - 70^\circ = 32^\circ$
$90^\circ - 32^\circ = 58^\circ$

In the figure below, not drawn to scale, PQST is a trapezium. PR // TS. Find $\angle$QRT.

$Question Image$

22$^\circ$

24$^\circ$

26$^\circ$

28$^\circ$

None of the above

Sorry. Please check the correct answer below.

$180^\circ - 104^\circ = 76^\circ$
$\angle$QST = $180^\circ - 102^\circ = 78^\circ$
$\angle$STR = $\angle$QRT = $180^\circ - 76^\circ - 78^\circ = 26^\circ$

View Correct Answer

26$^\circ$

You are Right

$180^\circ - 104^\circ = 76^\circ$
$\angle$QST = $180^\circ - 102^\circ = 78^\circ$
$\angle$STR = $\angle$QRT = $180^\circ - 76^\circ - 78^\circ = 26^\circ$

The figure below shows a trapezium ABCD. Given that AB//DC, $\angle$BAD = 105$^\circ$, and $\angle$BCD = 127$^\circ$, Find $\angle$ABC.

$Question Image$

51$^\circ$

53$^\circ$

55$^\circ$

57$^\circ$

None of the above

Sorry. Please check the correct answer below.

$\angle$ABC = $180^\circ - 127^\circ = 53^\circ$

View Correct Answer

53$^\circ$

You are Right

$\angle$ABC = $180^\circ - 127^\circ = 53^\circ$

What is the area of the trapezium below?

$Question Image$

110cm$^2$

112cm$^2$

114cm$^2$

116cm$^2$

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

112cm$^2$

You are Right

Name a trapezium in the figure below.

$Question Image$

SOP

OPQR

RQPS

SOT

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

RQPS

You are Right

The figure below shows a trapezium ABCD with AB // DC, $\angle$ DAB = 68 $^\circ$. And $\angle$ ABC is an isosceles triangle with AB = AD. Find $\angle$BCD.

$Question Image$

25$^\circ$

30$^\circ$

35$^\circ$

40$^\circ$

None of the above

Sorry. Please check the correct answer below.

30$^\circ$ $\rightarrow$ $\angle$ $ABD = (180^\circ-68^\circ) ÷ 2 = 56^\circ$
$\angle$ ABD = $\angle$ BDC
$\angle$ $BCD = 180^\circ – (94^\circ+56^\circ) = 30^\circ$

View Correct Answer

30$^\circ$

You are Right

30$^\circ$ $\rightarrow$ $\angle$ $ABD = (180^\circ-68^\circ) ÷ 2 = 56^\circ$
$\angle$ ABD = $\angle$ BDC
$\angle$ $BCD = 180^\circ – (94^\circ+56^\circ) = 30^\circ$

In the figure below, WXYZ is trapezium. Given that $\angle$WXY = 132$^\circ$ and $\angle$ZYW = 37$^\circ$, Find $\angle$XYW

$Question Image$

11$^\circ$

12$^\circ$

13$^\circ$

14$^\circ$

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

11$^\circ$

You are Right

Sign in to your account

Your student account is your portal to all things Udacity: your classroom, projects, forums, career resources, and more!

or sign in with one of these services

Create your student account

Your student account is your portal to all things Udacity: your classroom, projects, forums, career resources, and more!

or sign up with one of these services

PSLE-Math.com

Start winning at math! Be part of Singapore PSLE Math community and Unleash the Your Maths Potential!

General

About us
Contact us

Contact Us

6631-9759
admin@psle-math.com
https://psle-math.com

What subject area do you need help in?

Select level

Primary Secondary Junior College

Select subject

Maths Science Chinese English

Back

Ok, Let's confirm where you'll need help.

Enter your postal code.

Singapore

Back

Nice! 20 tutors are near you.

By clicking "Join now". you agree to our Terms of Use and Privacy Policy

Join now

Are you a Tutor or Tuition Center?

Tutor

Tuition Center

Back

Tell us about yourself

By clicking "Join now". you agree to our Terms of Use and Privacy Policy

Join now

Back

Your company's contact information

By clicking "Join now". you agree to our Terms of Use and Privacy Policy

Join now