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Question 1 of 25

The figure below shows a trapezium PQRS. What is the area of the shaded part?

$Question Image of The figure below shows a trapezium PQRS. What is the area of the shaded part? .$

43.5

45.5

47.5

49.5

None of the above

Sorry. Please check the correct answer below.

Area of Shaded Part = $\frac{1}{2} \times 9 \times 11 = 49.5$

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49.5

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Area of Shaded Part = $\frac{1}{2} \times 9 \times 11 = 49.5$

The figure is not drawn to scale. ABCD is a trapezium. Find $\angle$ADC.

$Question Image of The figure is not drawn to scale. ABCD is a trapezium. Find $\angle$ADC. .$

79$^\circ$

73$^\circ$

76$^\circ$

80$^\circ$

None of the above

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73$^\circ$

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In the figure below, not drawn to scale, ABCD is a trapezium. Find $\angle$ADB.

$Question Image$

10$^\circ$

15$^\circ$

20$^\circ$

25$^\circ$

None of the above

Sorry. Please check the correct answer below.

$180^\circ - 110^\circ = 70^\circ$
$180^\circ - 90^\circ - 45^\circ = 45^\circ$
$70^\circ - 45^\circ = 25^\circ$

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25$^\circ$

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$180^\circ - 110^\circ = 70^\circ$
$180^\circ - 90^\circ - 45^\circ = 45^\circ$
$70^\circ - 45^\circ = 25^\circ$

The figure below is not drawn to scale. ACDE is a trapezium. Given the AE = AB, $\angle$EAB =78$^\circ $ and $\angle$ACD is 90 $^\circ $ .
(a) Find $\angle$CDE.
(b) Find $\angle$ABE.
(c) Find $\angle$DEB.

$Question Image$

(a) 102$^\circ$
(b) 51$^\circ$
(c) 51$^\circ$

(a) 104$^\circ$
(b) 53$^\circ$
(c) 52$^\circ$

(a) 106$^\circ$
(b) 55$^\circ$
(c) 53$^\circ$

(a) 108$^\circ$
(b) 57$^\circ$
(c) 54$^\circ$

None of the above

Sorry. Please check the correct answer below.

(a) $180^\circ - 99^\circ = 81^\circ$
(b) $180^\circ - 78^\circ = 102^\circ$
$102^\circ ÷ 2 = 51^\circ$
(c) $\angle$DEB = $\angle$AEB = 51$^\circ$

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(a) 102$^\circ$
(b) 51$^\circ$
(c) 51$^\circ$

You are Right

(a) $180^\circ - 99^\circ = 81^\circ$
(b) $180^\circ - 78^\circ = 102^\circ$
$102^\circ ÷ 2 = 51^\circ$
(c) $\angle$DEB = $\angle$AEB = 51$^\circ$

In the figure below, WXYZ is trapezium. Given that $\angle$WXY = 132$^\circ$ and $\angle$ZYW = 37$^\circ$, Find $\angle$XYW

$Question Image$

11$^\circ$

12$^\circ$

13$^\circ$

14$^\circ$

None of the above

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11$^\circ$

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The figure below is not drawn to scale. ABCD is a trapezium and $\angle$ BDC = $\angle$ ADB. Find $\angle$ CAD.

$Question Image$

120$^\circ$

125$^\circ$

130$^\circ$

135$^\circ$

None of the above

Sorry. Please check the correct answer below.

120$^\circ$ $\rightarrow$ $360 – 280 = 80$
$80 ÷ 2 = 40$
$\angle$ CAD = $180^\circ - 40^\circ - 20^\circ = 120^\circ$

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120$^\circ$

You are Right

120$^\circ$ $\rightarrow$ $360 – 280 = 80$
$80 ÷ 2 = 40$
$\angle$ CAD = $180^\circ - 40^\circ - 20^\circ = 120^\circ$

In the figure, ABCD is a trapezium and BCD is an isosceles triangle. DB = DC, BAF = 52$^\circ$ and $\angle$AFE = 110$^\circ$. Find $\angle$BDC.

$Question Image$

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

You are Right

The line PQ and QR are part of an incomplete trapezium PQRS. Complete drawing the trapezium such that $\angle$QRS = 120$^\circ$. Measure the line PS.

$Question Image$

6.2cm

6.4cm

9.2cm

9.4cm

None of the above

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View Correct Answer

9.4cm

You are Right

The figure below shows a trapezium ABCD with AB // DC, $\angle$ DAB = 68 $^\circ$. And $\angle$ ABC is an isosceles triangle with AB = AD. Find $\angle$BCD.

$Question Image$

25$^\circ$

30$^\circ$

35$^\circ$

40$^\circ$

None of the above

Sorry. Please check the correct answer below.

30$^\circ$ $\rightarrow$ $\angle$ $ABD = (180^\circ-68^\circ) ÷ 2 = 56^\circ$
$\angle$ ABD = $\angle$ BDC
$\angle$ $BCD = 180^\circ – (94^\circ+56^\circ) = 30^\circ$

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30$^\circ$

You are Right

30$^\circ$ $\rightarrow$ $\angle$ $ABD = (180^\circ-68^\circ) ÷ 2 = 56^\circ$
$\angle$ ABD = $\angle$ BDC
$\angle$ $BCD = 180^\circ – (94^\circ+56^\circ) = 30^\circ$

In the figure, ABCD is a trapezium where AD is parallel to BC. Find $\angle$BDC.

$Question Image$

30$^\circ$

35$^\circ$

40$^\circ$

45$^\circ$

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

35$^\circ$

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The figure below shows a trapezium ABCD. AD is parallel to BE and BE = BC. $\angle$BEC = 70$^\circ$
(a) Find $\angle$ADC
(b) Find $\angle$ABC.

$Question Image$

(a) 50$^\circ$
(b) 100$^\circ$

(a) 60$^\circ$
(b) 105$^\circ$

(a) 70$^\circ$
(b) 110$^\circ$

(a) 80$^\circ$
(b) 115$^\circ$

None of the above

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View Correct Answer

(a) 70$^\circ$
(b) 110$^\circ$

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ABCD is a trapezium. AB is parallel to DC. Which one of the following statements is true?

$Question Image$

$\angle$DAB = $\angle$ADC

$\angle$DAB + $\angle$ADC = 180$^\circ$

$\angle$DAB + $\angle$ABC = 180$^\circ$

$\angle$DAB = $\angle$DCB

None of the above

Sorry. Please check the correct answer below.

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$\angle$DAB + $\angle$ADC = 180$^\circ$

You are Right

ABCD is a trapezium and EBD is an equilateral triangle. Find $\angle$ABE.

$Question Image$

18$^\circ$

20$^\circ$

22$^\circ$

24$^\circ$

None of the above

Sorry. Please check the correct answer below.

$\angle$ABE = $180^\circ - 110^\circ - 50^\circ = 20^\circ$

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20$^\circ$

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$\angle$ABE = $180^\circ - 110^\circ - 50^\circ = 20^\circ$

What is the area of the trapezium below?

$Question Image$

110cm$^2$

112cm$^2$

114cm$^2$

116cm$^2$

None of the above

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112cm$^2$

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In the figure below, not drawn to scale, PQST is a trapezium. PR // TS. Find $\angle$QRT.

$Question Image$

22$^\circ$

24$^\circ$

26$^\circ$

28$^\circ$

None of the above

Sorry. Please check the correct answer below.

$180^\circ - 104^\circ = 76^\circ$
$\angle$QST = $180^\circ - 102^\circ = 78^\circ$
$\angle$STR = $\angle$QRT = $180^\circ - 76^\circ - 78^\circ = 26^\circ$

View Correct Answer

26$^\circ$

You are Right

$180^\circ - 104^\circ = 76^\circ$
$\angle$QST = $180^\circ - 102^\circ = 78^\circ$
$\angle$STR = $\angle$QRT = $180^\circ - 76^\circ - 78^\circ = 26^\circ$

The figure below shows a trapezium ABCD. Given that AB//DC, $\angle$BAD = 105$^\circ$, and $\angle$BCD = 127$^\circ$, Find $\angle$ABC.

$Question Image$

51$^\circ$

53$^\circ$

55$^\circ$

57$^\circ$

None of the above

Sorry. Please check the correct answer below.

$\angle$ABC = $180^\circ - 127^\circ = 53^\circ$

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53$^\circ$

You are Right

$\angle$ABC = $180^\circ - 127^\circ = 53^\circ$

In the figure below, EBCD is a trapezium. ED is parallel to BC. $\angle$FAB = 74$^\circ$ and $\angle$EBC = 113$^\circ$. Find the sum of $\angle$w, $\angle$x, $\angle$y,and $\angle$z.

$Question Image$

213$^\circ$

215$^\circ$

217$^\circ$

219$^\circ$

None of the above

Sorry. Please check the correct answer below.

$180^\circ - 74^\circ = 106^\circ$ $\angle$y + $\angle$z
$180^\circ - 113^\circ = 67^\circ$
$180^\circ – 67^\circ = 113^\circ$ $\angle$x + $\angle$w
$113^\circ + 106^\circ = 219^\circ$

View Correct Answer

219$^\circ$

You are Right

$180^\circ - 74^\circ = 106^\circ$ $\angle$y + $\angle$z
$180^\circ - 113^\circ = 67^\circ$
$180^\circ – 67^\circ = 113^\circ$ $\angle$x + $\angle$w
$113^\circ + 106^\circ = 219^\circ$

In the figure, ABCD and EFGH are identical rhombuses and BKMN is a trapezium. Which one of the following statements is true?

$Question Image$

HE // GF // KM

AB // DC //KM

AD // BC // NM

HG // EF // NM

None of the above

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AD // BC // NM

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In the figure below, ABCD is a trapezium and PQCR is a square. The size of $\angle$DCR is $\frac{5}{4}$ of $\angle$DCQ. Find $\angle$DSQ?

$Question Image$

120$^\circ$

140$^\circ$

160$^\circ$

180$^\circ$

None of the above

Sorry. Please check the correct answer below.

$180 – 110 = 70$
$5 + 4 = 9$
$90 \div 9 = 10$
$10 \times 5 = 50$
$90 – 50 = 40$
$180 – 70 – 40 = 70$
$180 \times 2 = 360$
$\angle$DSQ = $360 – 70 – 79 – 40 = 160$

View Correct Answer

160$^\circ$

You are Right

$180 – 110 = 70$
$5 + 4 = 9$
$90 \div 9 = 10$
$10 \times 5 = 50$
$90 – 50 = 40$
$180 – 70 – 40 = 70$
$180 \times 2 = 360$
$\angle$DSQ = $360 – 70 – 79 – 40 = 160$

In the figure, YZ is a straight line while ABCD and PQRS are overlapping trapeziums. Given that $\angle$YAB = 50$^\circ$, $\angle$QDW = 135$^\circ$,$\angle$DQR = 60$^\circ$,
(a) Find $\angle$DXS.
(b) Find $\angle$QRW.

$Question Image$

(a) 50$^\circ$
(b) 75$^\circ$

(a) 60$^\circ$
(b) 80$^\circ$

(a) 70$^\circ$
(b) 85$^\circ$

(a) 80$^\circ$
(b) 90$^\circ$

None of the above

Sorry. Please check the correct answer below.

(a) $180^\circ - 50^\circ - 90^\circ = 40^\circ$
$180^\circ - 40^\circ - 90^\circ = 50^\circ$
(b) $180^\circ - 50^\circ = 130^\circ$
$360^\circ - 130^\circ - 135^\circ = 95^\circ$
$180^\circ - 45^\circ - 60^\circ = 75^\circ$

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(a) 50$^\circ$
(b) 75$^\circ$

You are Right

In the figure below, WXYZ is a trapezium. WZ is parallel to XY. $\angle$XWY = 52$^\circ$,$\angle$WYZ = 66 $^\circ$ and $\angle$WZY = 55$^\circ$. Find $\angle$WXY.

$Question Image$

56$^\circ$

58$^\circ$

60$^\circ$

62$^\circ$

None of the above

Sorry. Please check the correct answer below.

$180^\circ - 70^\circ - 70^\circ = 32^\circ$
$90^\circ - 32^\circ = 58^\circ$

View Correct Answer

58$^\circ$

You are Right

$180^\circ - 70^\circ - 70^\circ = 32^\circ$
$90^\circ - 32^\circ = 58^\circ$

Name a trapezium in the figure below.

$Question Image$

SOP

OPQR

RQPS

SOT

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

RQPS

You are Right

The figure below shows a trapezium. Which one of the following options is correct?

$Question Image$

$\angle$a = $\angle$c

$\angle$a = $\angle$b

$\angle$a + $\angle$b = $\angle$c + $\angle$d

$\angle$a +$\angle$d = $\angle$c + $\angle$b

None of the above

Sorry. Please check the correct answer below.

View Correct Answer

$\angle$a +$\angle$d = $\angle$c + $\angle$b

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In the figure below, not drawn to scale, WXYZ is a trapezium. AY, GW and YC are straight line. Find $\angle$YWX

$Question Image$

68$^\circ$

70$^\circ$

72$^\circ$

74$^\circ$

None of the above

Sorry. Please check the correct answer below.

$180^\circ - 78^\circ = 102^\circ$
$180^\circ - 102^\circ – 42^\circ= 36^\circ$
$(180^\circ - 36^\circ) ÷ 2= 72^\circ$

View Correct Answer

72$^\circ$

You are Right

$180^\circ - 78^\circ = 102^\circ$
$180^\circ - 102^\circ – 42^\circ= 36^\circ$
$(180^\circ - 36^\circ) ÷ 2= 72^\circ$

The figure shown below, a trapezium ABCD was folded as shown. AB is parallel to CD. AE is parallel to BF. $\angle$AEF = 65$^\circ$. Find $\angle$FAE.

$Question Image$

20$^\circ$

30$^\circ$

40$^\circ$

50$^\circ$

None of the above

Sorry. Please check the correct answer below.

$\angle$XDA $\rightarrow$ 65$^\circ$
$\angle$CDX $\rightarrow$ 65$^\circ$
$\angle$DXB $\rightarrow$ $180^\circ – 65^\circ = 115^\circ$
$\angle$DAX = $\angle$FAE $\rightarrow$ $150^\circ – 65^\circ = 50^\circ$

View Correct Answer

50$^\circ$

You are Right

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