In the diagram below, ABCD is a parallelogram. AC = CE = CF. $\angle$AEC = 55$^\circ $ and $\angle$AFC = 30$^\circ$ AF and CE are straight lines. Find $\angle$ABC.

The figure below is not drawn to scale. PQXS is a parallelogram, QRX and QXY are isosceles triangles, TW // PQ and $\angle$a PUT = 120 $^\circ$. SXR is a straight line. (a)Find$\angle$a RQX (b) Find$\angle$a SYQ